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azamat
1 year ago
15

A student sees an absorbance a=1.140 for his solution that has a concentration of c=1.50*10-4 m using 0.50 cm cuvette. what is t

he molar extinction coefficient for the compound?
Chemistry
1 answer:
777dan777 [17]1 year ago
6 0

The molar extinction coefficient is 15,200 M^{-1} cm^{-1}.

The formula to be used to calculate molar extinction coefficient is -

A = ξcl, where A represents absorption, ξ refers molar extinction coefficient, c refers to concentration and l represents length.

The given values are in required units, hence, there is no need to convert them. Directly keeping the values in formula to find the value of molar extinction coefficient.

Rewriting the formula as per molar extinction coefficient -

ξ = \frac{A}{cl}

ξ = \frac{1.140}{1.5*10^{-4}*0.5 }

Performing multiplication in denominator to find the value of molar extinction coefficient

ξ = \frac{1.140}{0.000075}  

Performing division to find the value of molar extinction coefficient

ξ = 15,200 M^{-1} cm^{-1}

Hence, the molar extinction coefficient is  15,200 M^{-1} cm^{-1}.

Learn more about molar extinction coefficient -

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Calculate the molarity of a solution that contains 3.00 grams Na2SO4 in 25 mL of solution.
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M Na2SO4 sln = 0.8448 M

Explanation:

  • molarity (M) [=] mol/L

∴ mass Na2SO4 = 3.00 g

∴ volume soln = 25 mL = 0.025 L

∴ molar mass Na2SO4 = 142.04 g/mol

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3 0
3 years ago
Calculate the work (kJ) done during a reaction in which the internal volume expands from 20 L to 43 L against an outside pressur
Alenkinab [10]

Answer:

\large \boxed{\text{-10.0 kJ}}

Explanation:

1. Calculate the work

w = - pΔV = -4.3 atm × (43 L - 20 L) = -4.3 × 23 L·atm = -98.9 L·atm

2. Convert litre-atmospheres to joules

w = \text{-98.9 L\cdot$atm } \times \dfrac{\text{101.3 J}}{\text{1 L$\cdot$atm }} = \text{-10000 J} = \textbf{-10.0 kJ}\\\\\text{The work done is $\large \boxed{\textbf{-10.0 kJ}}$}

The negative sign indicates that the work was done against the surroundings.

4 0
3 years ago
If a sample of CO gas at 1.977 atm has a volume of 517.4 mL and the pressure is changed to
Mekhanik [1.2K]

Answer:

The answer to your question is V2 = 333.9 ml

Explanation:

Data

Pressure 1 = P1 = 1.977 atm

Volume 1 = V1 = 517.4 ml

Pressure 2 = P2 = 3.063 atm

Volume 2 = V2 = ?

Process

To solve this problem use Boyle's law

              P1V1 = P2V2

-Solve for V2

              V2 = P1V1/P2

-Substitution

              V2 = (1.977 x 517.4) / 3.063

-Simplification

              V2 = 1022.9 / 3.063

-Result

              V2 = 333.9 ml

3 0
3 years ago
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