Answer:
the static charge is not always distributed on the surface of the conductor, there are also charges in the volume but of lesser magnitude
Explanation:
In this hypothetical system the electric force is of type
F =
in this case the force decays to zero much faster,
if we call Fo the force of Coulomb's law
F₀ = ![k \frac{q_1 q_2 }{r^2}](https://tex.z-dn.net/?f=k%20%5Cfrac%7Bq_1%20q_2%20%7D%7Br%5E2%7D)
assuming the constant k is the same
the relationship between the two forces is
F / F₀ = 1 / r
F = F₀ / r
when analyzing this expression the force decays much faster to zero.
In an electric conductor, charges of the same sign may not feel any repulsive force from other charges that are at a medium distance, so there is a probability that some charges are distributed in the volume of the material, this does not happen with coulomb's law
Consequently, the static charge is not always distributed on the surface of the conductor, there are also charges in the volume but of lesser magnitude
Answer:
<h3>The answer is 180 m</h3>
Explanation:
The distance covered by an object given it's velocity and time taken can be found by using the formula
distance = velocity × time
From the question we have
distance = 1.5 × 120
We have the final answer as
<h3>180 m</h3>
Hope this helps you
THE MOTION IS GOOD BECAUSE IT MAKES THE BATTER IT THE BALL AND THE BATTER LINES UP THE BALL AND BAT AND HE HITS IT
Answer:
Scientists have identified about a dozen major and several minor tectonic plates
Answer:
0.0769230769231 s
![4.6153846154\times 10^{-7}\ m](https://tex.z-dn.net/?f=4.6153846154%5Ctimes%2010%5E%7B-7%7D%5C%20m)
Explanation:
t = Time taken
u = Initial velocity = 0
v = Final velocity = 12 μm/s
s = Displacement
a = Acceleration = 156 μm/s²
From the linear equations of motion we have
![v=u+at\\\Rightarrow t=\dfrac{v-u}{a}\\\Rightarrow t=\dfrac{12\times 10^{-6}-0}{156\times 10^{-6}}\\\Rightarrow t=0.0769230769231\ s](https://tex.z-dn.net/?f=v%3Du%2Bat%5C%5C%5CRightarrow%20t%3D%5Cdfrac%7Bv-u%7D%7Ba%7D%5C%5C%5CRightarrow%20t%3D%5Cdfrac%7B12%5Ctimes%2010%5E%7B-6%7D-0%7D%7B156%5Ctimes%2010%5E%7B-6%7D%7D%5C%5C%5CRightarrow%20t%3D0.0769230769231%5C%20s)
Time taken to reach the required speed is 0.0769230769231 s
![s=ut+\dfrac{1}{2}at^2\\\Rightarrow s=0\times t+\dfrac{1}{2}\times 156\times 10^{-6}\times 0.0769230769231^2\\\Rightarrow s=4.6153846154\times 10^{-7}\ m](https://tex.z-dn.net/?f=s%3Dut%2B%5Cdfrac%7B1%7D%7B2%7Dat%5E2%5C%5C%5CRightarrow%20s%3D0%5Ctimes%20t%2B%5Cdfrac%7B1%7D%7B2%7D%5Ctimes%20156%5Ctimes%2010%5E%7B-6%7D%5Ctimes%200.0769230769231%5E2%5C%5C%5CRightarrow%20s%3D4.6153846154%5Ctimes%2010%5E%7B-7%7D%5C%20m)
The distance the bacterium will cover is ![4.6153846154\times 10^{-7}\ m](https://tex.z-dn.net/?f=4.6153846154%5Ctimes%2010%5E%7B-7%7D%5C%20m)