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Oduvanchick [21]
3 years ago
6

F = Gm2/r2 G = ? Fr2/m2 Fm2/r2 √(F)m/r √(F)r/m

Physics
1 answer:
trapecia [35]3 years ago
8 0

Answer: G=F\frac{r^{2}}{m^{2}}

Explanation:

We have the following equation:

F=G\frac{m^{2}}{r^{2}}

We have to find G this means we have to isolate it:

Fr^{2}=Gm^{2}

G=F\frac{r^{2}}{m^{2}}

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6 0
3 years ago
Which physical property is best measured using only a balance?
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The answer is C-Mass
6 0
3 years ago
A trumpet player is tuning his instrument by playing an A note simultaneously with the first-chair trumpeter, who has perfect pi
KIM [24]

To develop this problem, it is necessary to apply the concepts related to Beat

The Beat is an acoustic phenomenon that is generated by two sine waves interfering with slightly different frequencies. The beat frequency is equal to the difference in the frequencies of the two original waves:

f_{bat} = |(f_1 \pm f_B)|

Our values are given as

f_1 = 440Hz

f_B = 2.1Hz

For the particular case we have two possible frequencies:

1) f_{bat} = |(f_1 - f_B)|

f_{bat} = |(440 - 2.1)|

f_{bat} = 437.9Hz

2) f_{bat} = |(f_B + f_1)|

f_{bat} = |(440 +2.1)|

f_{bat} = 442.1Hz

Therefore the two possibles frequencies of the other players note are 437.9Hz and 442.1Hz

4 0
3 years ago
Four identical balls are thrown from the top of a cliff, each with the same speed. The
Jlenok [28]

Answer:

the speed and the kinetic energy of the first and fourth ball are equal, while the speed and kinetic energy of the second and third balls are equal

Explanation:

The kinetic energy, K.E. = (1/2) × m × v²

The velocity of the ball, v = u × sin(θ)

Where;

u = The initial velocity of the ball

θ = The reference angle

1) For the ball thrown straight up, we have;

θ = 90°

∴ v = u

The final velocity of the ball as it strikes the ground is v₂ = u² + 2gh

Where;

h = The height of the cliff

∴ K.E. = (1/2) × m × (u² + 2gh)²

2) For the second ball thrown 30° to the horizontal, we have;

K.E. = (1/2) × m × ((u×sin30)² + 2·g·h)² = K.E. = (1/2) × m × ((0.5·u)² + 2·g·h)²

3) For the third ball thrown at 30° below the horizontal, we have;

K.E. = (1/2) × m × ((u×sin30)² + 2·g·h)² = K.E. = (1/2) × m × ((0.5·u)² + 2·g·h)²

4)  For the fourth ball thrown straight down, we have;

K.E. = (1/2) × m × (u² + 2gh)²

Therefore, as the ball strike the ground, the speed and the kinetic energy of the first and fourth ball are equal, while the speed and kinetic energy of the second and third balls are equal

Learn more about object kinetic energy of object if free fall here;

brainly.com/question/14872097

6 0
3 years ago
REALICE UN ANALISIS DEL TEMA, INDICANDO LAS IDEAS PRINCIPALES
katen-ka-za [31]

Answer:

De cual Tema??? jajaja no se que necesitas

8 0
3 years ago
Read 2 more answers
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