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Oduvanchick [21]

3 years ago

6

F = Gm2/r2 G = ? Fr2/m2 Fm2/r2 √(F)m/r √(F)r/m

1 answer:

trapecia [35]3 years ago

8 0

Answer: $G=F\frac{r^{2}}{m^{2}}$

Explanation:

We have the following equation:

$F=G\frac{m^{2}}{r^{2}}$

We have to find $G$ this means we have to isolate it:

$Fr^{2}=Gm^{2}$

$G=F\frac{r^{2}}{m^{2}}$

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In some proton accelerators, proton beams are directed toward each other for head-on collisions. Suppose that in such an acceler

ipn [44]

Answer:

a) 0.9995c

b) 5641MeV

c) 91670 MeV

Explanation:

(a) The speed of approach is given by the formula:

$u=\frac{v_1+v_2}{1+\frac{v_1v_2}{c}}=\frac{2(0.9898c)}{1+\frac{(0.9898)^2c^2}{c^2}}=0.99995c$

(b) the kinetic energy is given by:

$E_k=m_0c^2[\frac{1}{\sqrt{1-\frac{v^2}{c^2}}}-1]$

by replacing c=3*10^8m/s, m_0=1.67*10^{-27}kg we obtain:

$E_k=5641MeV$

(c) in the rest frame of the other proton we have:

$E_k=m_0c^2[\frac{1}{\sqrt{1-\frac{u^2}{c^2}}}-1]$

by replacing we get

$E_k=91670MeV$

hope this helps!!

7 0

3 years ago

You can describe the of an object by saying it is moving in a straight line or it curved

Serga [27]

My answer -

You can tell the speed of a car at any instant by looking at curved path but it does not move with the average speed of any object moving in a straight line.

P.s

Happy to help you have a AWESOME!!!! day ^-^

8 0

3 years ago

A cat rides a merry-go-round while turning with uniform circular motion. At time t1 = 2.00 s, the cat's velocity is v with arrow

goldenfox [79]

Answer:

Part a)

$a_c = 2.07 m/s^2$

Part b)

$a_{avg} = 1.32 m/s^2$

Explanation:

As we know that it makes half revolution in given time interval

so we have

$\frac{T}{2} = t_2 - t_1$

$\frac{T}{2} = 9 - 2$

$T = 14 s$

now the angular speed is given as

$\omega = \frac{2\pi}{T}$

$\omega = \frac{2\pi}{14}$

$\omega = 0.448 rad/s$

now linear speed is given as

$v = \sqrt{2.30^2 + 4.00^2}$

$v = 4.61 m/s$

now we have

$v = R \omega$

$4.61 = R(0.448)$

$R = 10.3 m$

Now centripetal acceleration is given as

$a_c = \omega^2 R$

$a_c = 0.448^2 \times 10.3$

$a_c = 2.07 m/s^2$

Part b)

Average acceleration of the cat is given as

$a_{avg} = \frac{v_2 - v_1}{\Delta t}$

$a_{avg} = \frac{2v}{\Delta t}$

$a_{avg} = \frac{2(4.61)}{9 - 2}$

$a_{avg} = 1.32 m/s^2$

7 0

4 years ago

A 24-V battery is powering a light bulb with a resistance of 3.0 ohms. What is the current flowing through the bulb? A) 7.20 A B

Usimov [2.4K]

According to Ohm's law for a portion of the circuit we have:

U=RI=>I=U/R=24/3=8 A

The correct answer is B

3 0

3 years ago

How can gases have such a large impact on earths atmosphere

kozerog [31]

Answer:

well, the air in our atmosphere stays there and nothing can get past the last layer. Think of is as a car. if there gets to be too much gas in it, it can harm you. I would also say it is one of the causes of global warming. Also air pollution is a big problem.

Explanation:

8 0

3 years ago