The answer to the equation is
y=1700s+18n and y is the total salary including monthly and number books sold
then to graph it just plug that equation I gave you into your graphing calculator and it will show you the graph. Or you can do it by hand and just make a S and N table and plug in values like starting with 0 or 1 and go up 0,1,2,3,4,etc. for each S and P and you will get the corresponding graph coordinate points to plot. Hope this helps! Please rate thank you!!
Answer:
Shawn is correct.
Step-by-step explanation:
Let the quadratic function is g(x) = a(x - h)² + k
Here (h, k) is the vertex of the parabola.
Since this parabola passes through (0, 0), (1, 9) and (-1, 9), axis of symmetry is x = 0 and the vertex is (0, 0).
Therefore, equation of the parabola will be,
g(x) = a(x - 0)²+ 0
g(x) = ax²
for a point (1, 9) which lies on the graph,
9 = a(1)²
a = 9
g(x) = 9x² (here a > 1)
Therefore, f(x) is vertically stretched by a factor of 9 to form g(x).
Shawn is correct.
Step-by-step explanation:
x^2/9 z^2
hiiii checkout the steps
The simple interest of $4,700 principal at 4% interest and 10 months is <u>$156.67</u> and its <u>maturity level</u> is <u>83%</u>.
<h3>What is simple interest?</h3>
Simple interest refers to the interest calculated only on the principal.
With the simple interest method, the borrower only pays interest on the principal without considering the previously-accumulated interests.
<h3>Data and Calculations:</h3>
Principal = $4,700
Interest rate = 4%
Period = 10 months
Simple interest = $156.67 ($4,700 x 4% x 10/12)
Thus, the simple interest of $4,700 principal at 4% interest and 10 months is <u>$156.67</u> and its <u>maturity level</u> is <u>83%</u>.
Learn more about simple interests at brainly.com/question/
1. cot(x)sec⁴(x) = cot(x) + 2tan(x) + tan(3x)
cot(x)sec⁴(x) cot(x)sec⁴(x)
0 = cos⁴(x) + 2cos⁴(x)tan²(x) - cos⁴(x)tan⁴(x)
0 = cos⁴(x)[1] + cos⁴(x)[2tan²(x)] + cos⁴(x)[tan⁴(x)]
0 = cos⁴(x)[1 + 2tan²(x) + tan⁴(x)]
0 = cos⁴(x)[1 + tan²(x) + tan²(x) + tan⁴(4)]
0 = cos⁴(x)[1(1) + 1(tan²(x)) + tan²(x)(1) + tan²(x)(tan²(x)]
0 = cos⁴(x)[1(1 + tan²(x)) + tan²(x)(1 + tan²(x))]
0 = cos⁴(x)(1 + tan²(x))(1 + tan²(x))
0 = cos⁴(x)(1 + tan²(x))²
0 = cos⁴(x) or 0 = (1 + tan²(x))²
⁴√0 = ⁴√cos⁴(x) or √0 = (√1 + tan²(x))²
0 = cos(x) or 0 = 1 + tan²(x)
cos⁻¹(0) = cos⁻¹(cos(x)) or -1 = tan²(x)
90 = x or √-1 = √tan²(x)
i = tan(x)
(No Solution)
2. sin(x)[tan(x)cos(x) - cot(x)cos(x)] = 1 - 2cos²(x)
sin(x)[sin(x) - cos(x)cot(x)] = 1 - cos²(x) - cos²(x)
sin(x)[sin(x)] - sin(x)[cos(x)cot(x)] = sin²(x) - cos²(x)
sin²(x) - cos²(x) = sin²(x) - cos²(x)
+ cos²(x) + cos²(x)
sin²(x) = sin²(x)
- sin²(x) - sin²(x)
0 = 0
3. 1 + sec²(x)sin²(x) = sec²(x)
sec²(x) sec²(x)
cos²(x) + sin²(x) = 1
cos²(x) = 1 - sin²(x)
√cos²(x) = √(1 - sin²(x))
cos(x) = √(1 - sin²(x))
cos⁻¹(cos(x)) = cos⁻¹(√1 - sin²(x))
x = 0
4. -tan²(x) + sec²(x) = 1
-1 -1
tan²(x) - sec²(x) = -1
tan²(x) = -1 + sec²
√tan²(x) = √(-1 + sec²(x))
tan(x) = √(-1 + sec²(x))
tan⁻¹(tan(x)) = tan⁻¹(√(-1 + sec²(x))
x = 0
