Answer: (7.27%, 7.55%)
Step-by-step explanation:
As per given , we have
Sample size : n= 392
Sample mean : 

Critical two-tailed z-value for 95% confidence = 
Required confidence interval would be :

Hence, the required 95% confidence interval for the mean percentage share of billing volume from network television for the population of all U.S. advertising agencies : (7.27%, 7.55%)
Answer:
<h2>OOOOOOOOOOOOOO9ONOOOOOOOOOOOO</h2>
Multiply 5.2 x 30 and you get 156 miles
The percent increase in enrollment is 6 %
The operation used in first step is finding the difference between final value and initial value
<h3><u>Solution:</u></h3>
Given that This year, 1,272 students enrolled in night courses a a local college
Last year only 1,200 students enrolled.
To find: percent increase in the enrollment
The percent increase between two values is the difference between a final value and an initial value, expressed as a percentage of the initial value.
<em><u>The percent increase is given as:</u></em>

Here initial value (last year) = 1200 and final value(this year) = 1272
Substituting the values in above formula,

Thus percent increase is 6 %
ST=4
3x-8+x=2x
4x-8=2x
-8=-2x
4=x
Hope I’m not too late !