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USPshnik [31]
3 years ago
7

Heavenly body.

Physics
1 answer:
kicyunya [14]3 years ago
7 0

Answer:

768678677887667

Explanation:

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The height above the ground from where the skier start is 11.5 m.

<h3>Conservation of energy</h3>

The height above the ground from where the skier start is determined by applying the principle of conservation of energy as shown below;

P.E = K.E

mgh = ¹/₂mv²

gh = ¹/₂v²

h = \frac{v^2}{2g} \\\\h = \frac{15^2}{2 \times 9.8} \\\\h = 11.5 \ m

Thus, the height above the ground from where the skier start is 11.5 m.

Learn more about conservation of energy here: brainly.com/question/166559

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A 61 kg skier leaves the end of a ski-jump ramp with a velocity of 27 m/s directed 21° above the horizontal. Suppose that as a r
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Answer:

22kj

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set h = 0 at the end of slide.

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Final condition is Ui = mgh = 61 x 9.8 x -12 = -7173J

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Ki= 1/2 x 61 x (16)² = 7808J

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ΔEth = 22234.5 - 7808 + 7173

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3 years ago
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