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Doss [256]
3 years ago
9

Electron (-) has a charge of 1.6 x 10-19 C. Proton (+) has a charge of 1.6 x 10-19 C. In a hydrogen atom the distance between a

proton and an electron is
5.3 x 10-12 meter.
(A) Calculate the force acting between the proton and the electron. Show your work. Remember to include a correct force unit in your final answer.







(B) Why does it generally require energy (ionization energy) to remove an electron from an electron cloud? Hint: think of charges.



(C) To lift a 2lb dumbell off the floor to a height of your thigh would require about one Newton of force (1N). How many dumbells at once would you have to pick off a floor to your the height of your tight to show the magnitude of force acting between a proton and an electron?

2-lb dumbbell
Physics
1 answer:
gladu [14]3 years ago
7 0

Answer:

c because you can lift a 2 pound dumbell

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Plz help i beg, veryyy confused :)
pav-90 [236]
Displacement is distance in one particular direction. Distance is the route taken without worrying about the direction.
To find the displacement draw a straight line from the start point to the end point. Measure the length and use the scale to find the real distance.
Ask me if you need more help.
3 0
3 years ago
A bullet moving at a speed of 152 m/s passes through a plank of wood at 128m/s. Another bullet moving at 97m/s passes through th
Ivahew [28]

Answer:

The speed of the plank is 81.68 m/s

Explanation:

Given that,

Speed of bullet = 152 m/s

Speed of wood = 128 m/s

Speed of another bullet = 97 m/s

We need to calculate the speed of plank

Using conservation of momentum

m_{1}u_{1}=(m_{1}+m_{2})v

Where,

u = initial velocity

v = final velocity

152m_{1}=(m_{1}+m_{2})128....(I)

m_{1}97=(m_{1}+m_{2})v....(II)

From equation(I) and equation(II)

\dfrac{152}{97}=\dfrac{128}{v}

= \dfrac{128\times97}{152}

v=81.68\ m/s

Hence, The speed of the plank is 81.68 m/s

4 0
3 years ago
Darcy suffers from farsightedness equally severely in both eyes. The focal length of either of Darcy's eyes is 19.8 mm in its mo
bogdanovich [222]

Answer:

Explanation:

Power of defective eye = (1 / near point )+ (1 / lens-retina distance )

1 / .0198 m  =  (1 / near point )+ (1 / .02 m  )

= 50.50 = (1 / near point )+ 50

0.50 = 1 / near point

near point = 1 / .5 = 2m

= 200 cm .

for near point at 25 cm , convex lens will be required.

u = - 25 cm , v = - 200 cm ,

1 / v - 1 / u = 1 /f for lens

- 1 / 200 +  1 / 25 = 1 / f

= .04 - .005 = 1 /f

.035 = 1 / f

f = 28.57 cm = 0.2857 m

power = 1 /f

= 1 / 0.2857

= 3.5 D .

i v ) option is correct .

8 0
2 years ago
49. In what direction does the force of friction act?
liubo4ka [24]
Frictional force offers the resistance to the applied force opposing its motion. Thus, it always acts in the direction opposite to that of the object in motion. If force is applied to the left, then friction acts in the right.
6 0
2 years ago
State the conservation of momentum theorem
Luda [366]

Answer:

The total momentum of the two objects before the collision is equal to the total momentum of the two objects after the collision.

7 0
2 years ago
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