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4 years ago

Can someone answer this question please answer it correctly if it’s corect I will mark you brainliest

Mathematics

2 answers:

san4es73 [151]4 years ago

6 0

Answer:

$38.4

Step-by-step explanation:

20% discount means he has to pay:

100 - 20 = 80% of the marked price.

80/100 × 48 = 38.4

denis-greek [22]4 years ago

4 0

Answer:

$38.4

Step-by-step explanation:

To find the discounted price of a item, you need to apply the regular price and its sale percentage.

To find the "20% off sale" do this:

100% - 20% = 80%

Then multiply the regular price to the "80%".

Regular price of the watch: $48

Discounted price: $48 x 80% = $38.4

<h3><u><em>Hope this helps!!!</em></u></h3><h3><u><em>:)</em></u></h3>

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For $x$, $y$, and $z$ positive real numbers, what is the maximum possible value for\[\sqrt{\frac{3x 4y}{6x 5y 4z}} \sqrt{\frac{y

joja [24]

Answer:

Infinity

Step-by-step explanation:

Since x,y,z are positive rel numbers, we have that

$\dfrac{3x4y}{6x5y4z}=\dfrac{1}{10z}\\\\\\\dfrac{y2z}{6x5y4z}=\dfrac{1}{60x}\\\\\\\dfrac{2z3x}{6x5y4z}=\dfrac{1}{20y}$

Hence,

$\sqrt{\dfrac{3x4y}{6x5y4z}}\sqrt{\dfrac{y2z}{6x5y4z}}\sqrt{\dfrac{2z3x}{6x5y4z}}\\\\\\=\sqrt{\dfrac{1}{10z}\dfrac{1}{60x}\dfrac{1}{20y}}=\sqrt{\dfrac{1}{12000xyz}}$

Now let

$f(x,y,z)=\sqrt{\dfrac{1}{12000 xyz}}$

if we take x=y=1, we have

$f(1,1,z)=\sqrt{\dfrac{1}{12000z}}$

and so f(1,1,z) tends to infinity as z goes to 0.

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4 years ago