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Dima020 [189]
3 years ago
7

What larger class does DNA belong to?

Chemistry
2 answers:
serg [7]3 years ago
8 0

Answer:

It belongs to a class of molecules called the nucleic acids, which are polynucleotide.

Hope this helped! :)

vlada-n [284]3 years ago
5 0

Answer:DNA (or deoxyribonucleic acid) is the molecule that carries the genetic information in all cellular forms of life and some viruses. It belongs to a class of molecules called the nucleic acids, which are polynucleotides - that is, long chains of nucleotides.hope it helps

Explanation:

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The chemical formula for sodium citrate is Na3C6H5O7. Which statement is true? Sodium citrate is a compound with a total of 21 a
Scrat [10]

Answer:

Sodium citrate is a compound with a total of 21 atoms

6 0
3 years ago
Which subatomic particles are located in MOST of the space within an atom?
mote1985 [20]
The answer is particels of nuclis
5 0
3 years ago
How much pure acid is in 520 milliliters of a 13 ​% ​solution?
Liono4ka [1.6K]
It actually depends on the percentage of the concentration give. Percentages can be expressed as %mass/mass, %volume/volume or %mass/volume. To keep things simple, let's just assume that it is in %volume/volume. Thus, 13% of 520 mL is pure acid.

Volume of pure acid = 520*0.13 = 67.6 mL
4 0
3 years ago
How much energy must be removed from a 94.4 g sample of benzene (molar mass= 78.11 g/mol) at 322.0 K to solidify the sample and
Kay [80]

Answer : The energy removed must be, 29.4 kJ

Explanation :

The process involved in this problem are :

(1):C_6H_6(l)(322K)\rightarrow C_6H_6(l)(279K)\\\\(2):C_6H_6(l)(279K)\rightarrow C_6H_6(s)(279K)\\\\(3):C_6H_6(s)(279K)\rightarrow C_6H_6(s)(205K)

The expression used will be:  

Q=[m\times c_{p,l}\times (T_{final}-T_{initial})]+[m\times \Delta H_{fusion}]+[m\times c_{p,s}\times (T_{final}-T_{initial})]

where,

Q = heat released for the reaction = ?

m = mass of benzene = 94.4 g

c_{p,s} = specific heat of solid benzene = 1.51J/g^oC=1.51J/g.K

c_{p,l} = specific heat of liquid benzene = 1.73J/g^oC=1.73J/g.K

\Delta H_{fusion} = enthalpy change for fusion = -9.8kJ/mol=-\frac{9.8\times 1000J/mol}{78g/mol}=-125.6J/g

Now put all the given values in the above expression, we get:

Q=[94.4g\times 1.73J/g.K\times (279-322)K]+[94.4g\times -125.6J/g]+[94.4g\times 1.51J/g.K\times (205-279)K]

Q=-29427.312J=-29.4kJ

Negative sign indicates that the heat is removed from the system.

Therefore, the energy removed must be, 29.4 kJ

3 0
3 years ago
Write the correct chemical formula for potassium and sulfur
Shalnov [3]
Phosphorus + Sulfur ------> Phosphorus sulfide

2P + 3S ------> P2S3


Hope it helped!
3 0
3 years ago
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