Find the volume of the solid shown or described. If necessary round to the nearest tenth. What is the volume of the shed?
1 answer:
Answer:
Volume of shed = 38 m³
Step-by-step explanation:
Given:
Length = 5 m
Width = 2 m
Height of wall = 3 m
Height of triangular shed = 1.6 m
Find:
Volume of shed
Computation:
Volume of shed = Volume of walls + Volume of triangular shed
Volume of shed = [lbh] + [1/2][Base area]h
Volume of shed = [(5)(2)(3)] + [1/2][(5)(2)]1.6
Volume of shed = [30] + [8]
Volume of shed = 38 m³
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66 in
Explanation:
the circumference can be calculated as:
Where d is the diameter and π is 22/7.
So, replacing the values, we get:
Therefore, the circumference is 66 in.
The correct answer is: [C]: " a = ± 
" .
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Explanation:
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We are given:
_________________________________________________________
</span>→ " 25 = a² + b² " ; Solve for "a" ;
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→ To solve for "a" ; we want to isolate "a" on one side of the equation.
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We can rewrite: " 25 = a² + b² " ;
as: " a² + b² = 25 " .
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Then, we can subtract " b² " from each side of the equation; as follows:
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→ " a² + b² − b² = 25 − b² " ;
to get:
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→ " a² = 25 − b² " ;
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→ Now, take the square root of EACH SIDE of the equation ;
to isolate "a" on one side of the equation; & to solve for the value(s) of "a" ;
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→ √(a²) =
;
to get:
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→ a = | | ;
→ a = ± ;
→ which is: Answer choice: [C]: " a = ± " .
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<span>___________________________________________________________
Explanation:
_________________________________________________________
We are given:
_________________________________________________________
</span>→ " 25 = a² + b² " ; Solve for "a" ;
_________________________________________________________
→ To solve for "a" ; we want to isolate "a" on one side of the equation.
_________________________________________________________
We can rewrite: " 25 = a² + b² " ;
as: " a² + b² = 25 " .
_________________________________________________________
Then, we can subtract " b² " from each side of the equation; as follows:
_________________________________________________________
→ " a² + b² − b² = 25 − b² " ;
to get:
_________________________________________________________
→ " a² = 25 − b² " ;
_________________________________________________________
→ Now, take the square root of EACH SIDE of the equation ;
to isolate "a" on one side of the equation; & to solve for the value(s) of "a" ;
_________________________________________________________
→ √(a²) =
to get:
_____________________________________________________
→ a = |
→ a = ±
→ which is: Answer choice: [C]: " a = ±
______________________________________________________