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Karo-lina-s [1.5K]
3 years ago
12

How many moles are in 325 mL Ne at STP?

Chemistry
1 answer:
Slav-nsk [51]3 years ago
6 0

Hey there!

325 mL in liters:

325 / 1000 => 0.325 L

1 mole ( Ne ) ------------- 22.4 L ( at STP )

moles ( Ne ) ------------ 0.325 L

moles Ne = 0.325 * 1 / 22.4

moles Ne = 0.325 / 22.4

moles Ne = 0.0145 moles

hope this helps!

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1) Fist of all we need to calculate the standard cell potential, one should look up the reduction potentials for the species envolved:

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(overall) 2MnO_{4 (aq)}+3Cu_{(s)}+8H^{+}_{(aq)}→3Cu^{2+}_{(aq)}+2MnO_{2 (aq)}+4H_{2}O E°=1.342 v

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Knowing the standard potential, one calculates the nonstandard potential using the Nernst Equation:

E=E^{0} -\frac{RT}{nF}Ln\frac{[red]}{[ox]}

Where 'R' is the molar gas constant, 'T' is the kelvin temperature, 'n' is the number of electrons involved in the reaction and 'F' is the faraday constant.

The problem gives the [red]=0.66M and [ox]=1.69M, just apply to the Nernst Equation to give

E=1.342 -\frac{298.15*8.314}{6*96500}Ln\frac{[.66]}{[1.69]}=1.346

E=1.346

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