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Karo-lina-s [1.5K]
3 years ago
12

How many moles are in 325 mL Ne at STP?

Chemistry
1 answer:
Slav-nsk [51]3 years ago
6 0

Hey there!

325 mL in liters:

325 / 1000 => 0.325 L

1 mole ( Ne ) ------------- 22.4 L ( at STP )

moles ( Ne ) ------------ 0.325 L

moles Ne = 0.325 * 1 / 22.4

moles Ne = 0.325 / 22.4

moles Ne = 0.0145 moles

hope this helps!

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General Chemistry fourth edition by McQuarrie, Rock, and Gallogly. University Science Books presented by Macmillan Learning.
Helen [10]

Answer:

3.07 Cal/g

Explanation:

Step 1: Calculate the heat absorbed by the calorimeter

We will use the following expression.

Q = C × ΔT

where,

  • Q: heat absorbed
  • C: heat capacity of the calorimeter (37.60 kJ/K = 37.60 kJ/°C)
  • ΔT: temperature change (2.29 °C)

Q = 37.60 kJ/°C × 2.29 °C = 86.1 kJ

According to the law of conservation of energy, the heat released by the candy has the same magnitude as the heat absorbed by the calorimeter.

Step 2: Convert 86.1 kJ to Cal

We will use the conversion factor 1 Cal = 4.186 kJ.

86.1 kJ × 1 Cal/4.186 kJ = 20.6 Cal

Step 3: Calculate the number of Cal per gram of candy

20.6 Cal/6.70 g = 3.07 Cal/g

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Nitrogen atom is small in size than phosphorus thus the bond between its nucleus and valence electrons are stronger than phosphorus.

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Explanation:

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