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Doss [256]
3 years ago
5

Give the reason for the evaporation of the solution to dryness with 6 m hcl in the first procedure of the copper-arsenic group a

nalysis. include net ionic equations for any reactions that occur.
Chemistry
1 answer:
SCORPION-xisa [38]3 years ago
4 0
<span>
Evaporation occurred between the reaction of the hydrochloric acid and the arsenic group because there is a formation of gas. A liquid is cooled if condensation exceeds evaporation. This is because the cooling of the liquid decreases the kinetic energy of the molecules. Their movement is being restricted by the colder temperature. The molecules tend to be closer with each other. Also, because of their restricted movement, the liquid may turn into solid due the colder temperature. An example of this is the cooling of liquid water by placing it into the refrigerator into solid water (ice).</span>
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Shtirlitz [24]

Answer:

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For parts a &amp; b below, derive only the initial value problem set up.
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Explanation:

From the given information:

Let y(t) be the amount of sugar in tank A at any time.

Then, the rate of change of sugar in the tank is given by:

\dfrac{dy}{dt}= (rate \ in ) - ( rate \ out )

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\text{rate of sugar going out }= \dfrac{y(t) \ pound}{100}\times \dfrac{1 }{min} \\ \\ = \dfrac{y}{100} \ pound/min

So; \\ \\ \\ \dfrac{dy}{dt} = 0 - \dfrac{y}{100}  \\ \\ \implies \dfrac{dy}{y }= -\dfrac{dt}{100 } \\ \\ \implies dx|y| = -\dfrac{t}{100}+C  \\ \\  \implies e*{In|y|}= e^{-\dfrac{t}{100}+C} \\ \\ \implies y = Ce^{-\dfrac{t}{100}}

Initial amount of sugar = 25 Pounds

Now; y(0) = 25

25 = Ce⁰

C = 25

So;  y(t) = 25 e^{-\dfrac{t}{100}

Thus, the amount of sugar at any time t = \mathbf{25 e^{^{-\dfrac{t}{100}}}}

B) For tank B :

\dfrac{dy}{dt}= 1 - \dfrac{y}{50 } \\ \\ \dfrac{dy}{dt}= \dfrac{50-y}{50} \\ \\  \dfrac{dy}{50-y }= \dfrac{dt}{50}

8 0
3 years ago
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