The unbalanced equation is BF3 + Li2 SO3 --> B2 (SO3)3 + LiF, where the numbers to the right of the symbols are subscripts. The balanced equation is 2 BF3 + 3 Li2SO3 ---> B2 (SO3)3 + 6LiF. The numbers in front of every formula (compound) are the respective coefficients. You can check that the equation is balanced counting every element: There are 2B in the side of the reactants and 2B in the side of the products; there are 6F in the side of the reactants and 6F in the side of the products; there are 6 Li in the side of the reactants and 6 Li in the side of the products; and there are 3 SO3 in the side of the reactants and 3 SO3 in the side of the products. <span>So, the coefficient of the LiF is 6.</span>
NiF2 is the correct answer for the is problem
It's A; decomposition reactions involve one reactant becoming 2 or more products.
The equilibria showing how the acetate buffer adjusts to addition of a small amount of NaOH is:
- CH3COOH(aq) + H2O(1) → H30+ (aq) + CH3COO (aq)
<h3>What is a buffer?</h3>
A buffer is a solution which resists changes to its pH when small amounts of strong base or acid is added to it.
Buffers are made from solutions of weak acids and their salts or weak bases and their salts.
The equilibria showing how a buffer made from acetic acid and sodium acetate (NaCH3COO) adjusts to addition of a small amount of NaOH is as follows:
- CH3COOH(aq) + H2O(1) → H30+ (aq) + CH3COO (aq)
Addition of NaOH, a strong base will neutralize the hydronium ion, causing the acetic acid ionization equilibrium to shift to the right to produce more of the acetate ion, the conjugate base.
Learn more about acetate buffer at: brainly.com/question/17490438
