Question

How many grams of barium chloride (BaCl2) are there in 0.187 mol? 0.187 mol

Answer 1

Answer:

38.9 grams of $BaCl_2$

Explanation:

0.187 mol BaCl2 x $\frac{208 g}{1 mol}$

0.187 m x 208 g/m

0.187 x 208 g

38.896 g --> 38.9 g BaCl2