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3 years ago

How many grams of barium chloride (BaCl2) are there in 0.187 mol? 0.187 mol

Chemistry

1 answer:

igor_vitrenko [27]3 years ago

8 0

Answer:

38.9 grams of $BaCl_2$

Explanation:

0.187 mol BaCl2 x $\frac{208 g}{1 mol}$

0.187 m x 208 g/m

0.187 x 208 g

38.896 g --> 38.9 g BaCl2

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