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3 years ago

Can someone anyone help me out please

Mathematics

1 answer:

Hunter-Best [27]3 years ago

6 0

Answer:

2:9

Step-by-step explanation:

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What is the solution set for |-x|=-x

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3 years ago

Question 5 pleaseeee

vovikov84 [41]

Answer:

first

Step-by-step explanation:

f(n) =56 (0.5)^(n-1)

f(1) = 56 (0.5)^0= 56*1 = 56

f(2) =56 (0.5)^1 = 56* 0.5 = 28

f(3) = 56 (0.5)^2 = 14

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3 years ago

What is the measure of angle R?

Alika [10]

Answer:

m<R = 22.62°

Step-by-step explanation:

Reference angle = R

Opposite = 5 cm

Hypotenuse = 13 cm

Apply the trigonometric function SOH:

Sin R = Opp/Hyp

$Sin (R) = \frac{5}{13}$

$R = sin^{-1}(\frac{5}{13})$

R = 22.6198649°

m<R = 22.62° (nearest hundredth)

3 0

3 years ago

A lot of 25 skylight covers are received at your construction site, and before installation are subjected to an acceptance testi

8090 [49]

Answer:

If the lot has 4 defective covers out of 25 total covers, the probability of accepting the lot is P=0.98.

Step-by-step explanation:

We have a population of N=25 skylight covers, were K=4 are defective.

We sample n=5 covers, and we will accept the lot if k=2 or fewer are defective.

We will use the hypergeometric distribution to model this probabilities.

First, to be accepted, the sample can have 2, 1 or 0 defective covers, so the probability of being accepted is:

$P(accepted)=P(k\leq2)=P(k=0)+P(k=1)+P(k=2)$

The probability that there are k defective covers in the sample is:

$P(k)=\dfrac{\dbinom{k}{k}\dbinom{N-k}{n-k}}{\dbinom{N}{n}}$

Then, we can calculate the individual probabilities as:

$P(k=0)=\dfrac{\dbinom{4}{0}\cdot \dbinom{25-4}{5-0}}{\dbinom{25}{5}}=\dfrac{\dbinom{4}{0}\cdot \dbinom{21}{5}}{\dbinom{25}{5}}\\\\\\P(k=0)=\dfrac{1\cdot 20349}{53130}=0.38$

$P(k=1)=\dfrac{\dbinom{4}{1}\cdot \dbinom{25-4}{5-1}}{\dbinom{25}{5}}=\dfrac{\dbinom{4}{1}\cdot \dbinom{21}{4}}{\dbinom{25}{5}}\\\\\\P(k=1)=\dfrac{4\cdot 5985}{53130}=0.45$

$P(k=2)=\dfrac{\dbinom{4}{2}\cdot \dbinom{25-4}{5-2}}{\dbinom{25}{5}}=\dfrac{\dbinom{4}{2}\cdot \dbinom{21}{3}}{\dbinom{25}{5}}\\\\\\P(k=2)=\dfrac{6\cdot 1330}{53130}=0.15$

If we add this probabilities, we have:

$P(accepted)=P(k\leq2)=P(k=0)+P(k=1)+P(k=2)\\\\P(accepted)=0.38+0.45+0.15=0.98$

If the lot has 4 defective covers out of 25 total covers, the probability of accepting the lot is P=0.98.

6 0

3 years ago