<span> I suppose carbon dioxide produced from burning coal and oil can be recycled and converted to methanol. i hope this answers your question</span>
The percent yield is given by the actual and the theoretical yield. The percent yield of the 2.73 gm compound is 80.3%. Thus, option b is correct.
<h3>What is the percent yield?</h3>
The percent yield is the ratio of the actual yield to the theoretical yield. It is calculated as:
% Yield = Actual yield ÷ Theoretical yield × 100%
= 2.73 ÷ 3.84 × 100%
= 71.09 %
As the closest number to 71.09 is 80.3% the percent yield will be 80.3%.
There is no limiting reagent in the reaction between the copper iodide and mercury iodide as the moles of the reactants and the products are in equal quantity.
Hence, option b. there is no limiting reagent in this reaction.
Learn more about percent yield here:
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Answer: The enthalpy of the given reaction is 1234.8kJ/mol.
Explanation: Enthalpy change of the reaction is the amount of heat released or absorbed in a given chemical reaction.
Mathematically,

For the given reaction:





![\Delta H_{rxn}=\Delta H_f_{(C_2H_5OH)}+3\Delta H_f_{(O_2)}-[2\Delta H_f_{(CO_2)}+3\Delta H_f_{(H_2O)}]](https://tex.z-dn.net/?f=%5CDelta%20H_%7Brxn%7D%3D%5CDelta%20H_f_%7B%28C_2H_5OH%29%7D%2B3%5CDelta%20H_f_%7B%28O_2%29%7D-%5B2%5CDelta%20H_f_%7B%28CO_2%29%7D%2B3%5CDelta%20H_f_%7B%28H_2O%29%7D%5D)
Putting values in above equation, we get:
![\Delta H_{rxn}=[-277.6+3(0)]-[2(-393.5)+3(-241.8)]kJ/mol](https://tex.z-dn.net/?f=%5CDelta%20H_%7Brxn%7D%3D%5B-277.6%2B3%280%29%5D-%5B2%28-393.5%29%2B3%28-241.8%29%5DkJ%2Fmol)

Ba(OH)2 dissociates according to the equation below to yield Barium ions and hydroxide ions.
Ba(OH)2 = Ba²⁺ + 2 OH⁻
The concentration of Ba²⁺ is 1.0 ×10^-3 M
Thus that of OH⁻ ions will be 2× 1.0 ×10^-3 = 2.0 × 10^-3 M
Thus; the answer is 2.0 × 10^-3 M
Inquiry; wanting to know. Thinking critically to figure out, understand. However being skeptic to not fall on one simple answer. For possibly, it could be incorrect.