Answer: The density of lead will be
Explanation:
Density is defined as the mass contained per unit volume.
Given : Mass of lead=
Volume of lead =
Putting in the values we get:
Thus density of lead will be
I believe Winter is <span>your answer.</span>
<h3>
Answer:</h3>
= 5.79 × 10^19 molecules
<h3>
Explanation:</h3>
The molar mass of the compound is 312 g/mol
Mass of the compound is 30.0 mg equivalent to 0.030 g (1 g = 1000 mg)
We are required to calculate the number of molecules present
We will use the following steps;
<h3>Step 1: Calculate the number of moles of the compound </h3>
Therefore;
Moles of the compound will be;
= 9.615 × 10⁻5 mole
<h3>Step 2: Calculate the number of molecules present </h3>
Using the Avogadro's constant, 6.022 × 10^23
1 mole of a compound contains 6.022 × 10^23 molecules
Therefore;
9.615 × 10⁻5 moles of the compound will have ;
= 9.615 × 10⁻5 moles × 6.022 × 10^23 molecules
= 5.79 × 10^19 molecules
Therefore the compound contains 5.79 × 10^19 molecules
Answer:
The answer to your question is below
Explanation:
H₂SO₄ = sulphuric acid
KOH = potassium hydroxide
This is a neutralization reaction
H₂SO₄ + 2 KOH ⇒ K₂SO₄ + 2H₂O
2 ----------- K ----------- 2
1 ----------- S ---------- 1
4 ---------- H --------- 4
6 ------------ O ---------- 6
Answer: <u>Arabic</u>
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