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2 years ago

Find the probability of showing multiples of 4 on the first die

Mathematics

2 answers:

sp2606 [1]2 years ago

8 0

Answer:

1/6

Step-by-step explanation:

If this is a normal 6 sided she, there is only one multiple of 4 possible.

So, the probability is 1/6

Yuliya22 [10]2 years ago

7 0

The answer would be 1/6

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Evaluate the expression. (8 − 5)3 − 24

Amiraneli [1.4K]

Answer:

-15

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Supriya is decorating her bedroom. She plans to hang strings of twinkle lights all the way around her walls. She measures the wa

masha68 [24]

Answer:

Perimeter

Step-by-step explanation:

Perimeter is the distance all round a particular shape. Since we are not given the shape of her bedroom, we may not have a particular formula that was uses to find the perimeter. Despite all that, the only way that she could arrive to conclusion that 36 meters of light are needed, then Supriya it is by finding the perimeter.

4 0

3 years ago

A rectangle made of square tiles measures 7 tiles long and 3 tiles wide. what is the length of a similar rectangle whose width i

Norma-Jean [14]

The length of the rectangle would be 21

Proportion to set it up would be 7/3 x X/9 cross multiply and solve for x which is 21

6 0

2 years ago

What equation is the inverse of y=2x^2-8?

Fynjy0 [20]

Step-by-step explanation:

To get the inverse, swap the x- and y-variables, then solve for y. We should have the equation: $x = 2y^2 - 8$

Solving for y:

$y = 2x^{2} - 8$ because $y + 8 = 2x^{2}$ or $x =\sqrt\frac{y + 8}{2}$

So on interchanging the variable, we get the equation:

$x = 2y^2 - 8$

$x + 8 = 2y^2$

$y = \sqrt\frac{x + 8}{2}$

5 0

2 years ago

Please help me with this

denis23 [38]

Answer:

20) $\displaystyle [4, 1]$

19) $\displaystyle [-5, 1]$

18) $\displaystyle [3, 2]$

17) $\displaystyle [-2, 1]$

16) $\displaystyle [7, 6]$

15) $\displaystyle [-3, 2]$

14) $\displaystyle [-3, -2]$

13) $\displaystyle NO\:SOLUTION$

12) $\displaystyle [-4, -1]$

11) $\displaystyle [7, -2]$

Step-by-step explanation:

20) {−2x - y = −9

{5x - 2y = 18

⅖[5x - 2y = 18]

{−2x - y = −9

{2x - ⅘y = 7⅕ >> New Equation

__________

$\displaystyle \frac{-1\frac{4}{5}y}{-1\frac{4}{5}} = \frac{-1\frac{4}{5}}{-1\frac{4}{5}}$

$\displaystyle y = 1$ [Plug this back into both equations above to get the x-coordinate of 4]; $\displaystyle 4 = x$

_______________________________________________

19) {−5x - 8y = 17

{2x - 7y = −17

−⅞[−5x - 8y = 17]

{4⅜x + 7y = −14⅞ >> New Equation

{2x - 7y = −17

_____________

$\displaystyle \frac{6\frac{3}{8}x}{6\frac{3}{8}} = \frac{-31\frac{7}{8}}{6\frac{3}{8}}$

$\displaystyle x = -5$ [Plug this back into both equations above to get the y-coordinate of 1]; $\displaystyle 1 = y$

_______________________________________________

18) {−2x + 6y = 6

{−7x + 8y = −5

−¾[−7x + 8y = −5]

{−2x + 6y = 6

{5¼x - 6y = 3¾ >> New Equation

____________

$\displaystyle \frac{3\frac{1}{4}x}{3\frac{1}{4}} = \frac{9\frac{3}{4}}{3\frac{1}{4}}$

$\displaystyle x = 3$ [Plug this back into both equations above to get the y-coordinate of 2]; $\displaystyle 2 = y$

_______________________________________________

17) {−3x - 4y = 2

{3x + 3y = −3

__________

$\displaystyle \frac{-y}{-1} = \frac{-1}{-1}$

$\displaystyle y = 1$ [Plug this back into both equations above to get the x-coordinate of −2]; $\displaystyle -2 = x$

_______________________________________________

16) {2x + y = 20

{6x - 5y = 12

−⅓[6x - 5y = 12]

{2x + y = 20

{−2x + 1⅔y = −4 >> New Equation

____________

$\displaystyle \frac{2\frac{2}{3}y}{2\frac{2}{3}} = \frac{16}{2\frac{2}{3}}$

$\displaystyle y = 6$ [Plug this back into both equations above to get the x-coordinate of 7]; $\displaystyle 7 = x$

_______________________________________________

15) {6x + 6y = −6

{5x + y = −13

−⅚[6x + 6y = −6]

{−5x - 5y = 5 >> New Equation

{5x + y = −13

_________

$\displaystyle \frac{-4y}{-4} = \frac{-8}{-4}$

$\displaystyle y = 2$ [Plug this back into both equations above to get the x-coordinate of −3]; $\displaystyle -3 = x$

_______________________________________________

14) {−3x + 3y = 3

{−5x + y = 13

−⅓[−3x + 3y = 3]

{x - y = −1 >> New Equation

{−5x + y = 13

_________

$\displaystyle \frac{-4x}{-4} = \frac{12}{-4}$

$\displaystyle x = -3$ [Plug this back into both equations above to get the y-coordinate of −2]; $\displaystyle -2 = y$

_______________________________________________

13) {−3x + 3y = 4

{−x + y = 3

−⅓[−3x + 3y = 4]

{x - y = −1⅓ >> New Equation

{−x + y = 3

________

$\displaystyle 1\frac{2}{3} ≠ 0; NO\:SOLUTION$

_______________________________________________

12) {−3x - 8y = 20

{−5x + y = 19

⅛[−3x - 8y = 20]

{−⅜x - y = 2½ >> New Equation

{−5x + y = 19

__________

$\displaystyle \frac{-5\frac{3}{8}x}{-5\frac{3}{8}} = \frac{21\frac{1}{2}}{-5\frac{3}{8}}$

$\displaystyle x = -4$ [Plug this back into both equations above to get the y-coordinate of −1]; $\displaystyle -1 = y$

_______________________________________________

11) {x + 3y = 1

{−3x - 3y = −15

___________

$\displaystyle \frac{-2x}{-2} = \frac{-14}{-2}$

$\displaystyle x = 7$ [Plug this back into both equations above to get the y-coordinate of −2]; $\displaystyle -2 = y$

I am delighted to assist you anytime my friend!

7 0

3 years ago