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SSSSS [86.1K]
4 years ago
14

What is the largest integer $n$ such that $7^n$ divides $1000!$ ?

Mathematics
1 answer:
stiks02 [169]4 years ago
6 0

Answer:

The correct answer is

n = 3038

Step-by-step explanation:

Where we have;

We note that 1000! = An even number

Since Even × Even = even

Even × Odd = Even

Also, 7ⁿ is an Odd number since odd × odd = odd

Therefore 7ⁿ will divide 1000! with some fractions as follows;

1000! divided by 7ⁿ

When 7ⁿ = 1000!

log(7ⁿ) = log(1000!) = log(4.02×10²⁵⁶⁷)

n·log(7) = 2567.604

n = 2567.604/(log(7)) = 3038.23

Therefore, the largest integer n such that 7ⁿ divides 1000! = 3038

Which gives, 1000! ÷ 7³⁰³⁸ = 1.5733.

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3 years ago
If f(x)=2x+3 and g(x)=x^2+1 find f(g(3))<br><br> Help!!<br> A.23<br> B.47<br> C.82<br> D.90
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Answer

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step-by-step explanation

g(x) =  {x}^{2} + 1

We put x=3 into the function g

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Also,

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we substitute the value of g(3) into f

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Answer:

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