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Leya [2.2K]
3 years ago
15

How does a new hypothesis replace an order exclamation of something in the natural world

Chemistry
1 answer:
horrorfan [7]3 years ago
8 0
The knowledge gained by observing the natural world. Scientific ... New data can lead a scientist to change their hypothesis. A series of ... A. They always involves seeing something.
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A 12.0% sucrose solution by mass has a density of 1.05 gem, what mass of sucrose is present in a 32.0-mL sample of this solution
natulia [17]

Answer:

Option C. 4.03 g

Explanation:

Firstly we analyse data.

12 % by mass, is a sort of concentration. It indicates that in 100 g of SOLUTION, we have 12 g of SOLUTE.

Density is the data that indicates grams of solution in volume of solution.

We need to determine, the volume of solution for the concentration

Density = mass / volume

1.05 g/mL = 100 g / volume

Volume =  100 g / 1.05 g/mL → 95.24 mL

Therefore our 12 g of solute are contained in 95.24 mL

Let's finish this by a rule of three.

95.24 mL contain 12 g of sucrose

Our sample of 32 mL may contain ( 32 . 12) / 95.24 = 4.03 g

7 0
3 years ago
What are three ways of the atmosphere is important to living things?
UNO [17]
  <span>1. Blocks Ultra violet rays that can be harmful.
2. Provides Oxygen, so we can live. 
3. It blocks meteors from hitting Earth's surface. 
</span><span>
</span>
7 0
3 years ago
____________ tautomers have a C=O and an additional C-H bond.
Roman55 [17]

Ch = sh = why and find the stuff

4 0
4 years ago
Which bond is most polar c-o h-o n-o s-o
scZoUnD [109]

Answer:

Option 4 with o-h in the most polar bond, since the two atoms in the bond have the greatest difference in electronegativity.  This is assuming there are no other factors in other atoms bound to either of the elements in the bond.

Explanation:

6 0
3 years ago
A certain gas at 2oC and 1.00 atm pressure fills a 4.0 container. What volume will the gas occupy at 100oC and 780 torr pressure
artcher [175]

The final volume V₂=4.962 L

<h3>Further explanation</h3>

Given

T₁=20 + 273 = 293 K

P₁= 1 atm

V₁ = 4 L

T₂=100+273 = 373 K

P₂=780 torr=1,02632 atm

Required

The final volume

Solution

Combined gas law :

P₁V₁/T₁=P₂V₂/T₂

Input the value :

V₂=(P₁V₁T₂)/(P₂T₁)

V₂=(1 x 4 x 373)/(1.02632 x 293)

V₂=4.962 L

6 0
3 years ago
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