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3 years ago

The President's Challenge Program is a fitness evaluation designed for __________.

Chemistry

2 answers:

Paraphin [41]3 years ago

8 0

Answer:

The answer is B

Explanation:

Took on EDGE2020

lara [203]3 years ago

7 0

Hi there!

I believe the answer to this is B. Elementary and High school students.

Hope this helps! ☺♥

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zavuch27 [327]

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3 years ago

5. Azulene is a beautiful blue hydrocarbon. If 0.106 g of the compound is burned in oxygen, 0.364 g of CO2 and 0.0596 g of H2O a

max2010maxim [7]

Answer: The empirical and molecular formula for the given organic compound is CH and $C_{10}H_{10}$ and it is not an alkane.

Explanation:

The chemical equation for the combustion of hydrocarbon having carbon and hydrogen follows:

$C_xH_y+O_2\rightarrow CO_2+H_2O$

where, 'x' and 'y' are the subscripts of Carbon, hydrogen and oxygen respectively.

We are given:

Mass of $CO_2=0.364g$

Mass of $H_2O=0.0596g$

We know that:

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

For calculating the mass of carbon:

In 44 g of carbon dioxide, 12 g of carbon is contained.

So, in 0.364 g of carbon dioxide, $\frac{12}{44}\times 0.364=0.0993g$ of carbon will be contained.

For calculating the mass of hydrogen:

In 18 g of water, 2 g of hydrogen is contained.

So, in 0.0596 g of water, $\frac{2}{18}\times 0.0596=0.0067g$ of hydrogen will be contained.

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon = $\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{0.0993g}{12g/mole}=0.00828moles$

Moles of Hydrogen = $\frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{0.0067g}{1g/mole}=0.0067moles$ ]

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.0067 moles.

For Carbon = $\frac{0.00828}{0.0067}=1.23\approx 1$

For Hydrogen = $\frac{0.0067}{0.0067}=1$

Step 3: Taking the mole ratio as their subscripts.

The ratio of C : H = 1 : 1

The empirical formula for the given compound is CH

For determining the molecular formula, we need to determine the valency which is multiplied by each element to get the molecular formula.

The equation used to calculate the valency is:

$n=\frac{\text{Molecular mass}}{\text{Empirical mass}}$

We are given:

Mass of molecular formula = 128.2 g/mol

Mass of empirical formula = 13 g/mol

Putting values in above equation, we get:

$n=\frac{128.2g/mol}{13g/mol}=9.86\approx 10$

Multiplying this valency by the subscript of every element of empirical formula, we get:

$C_{(1\times 10)}H_{(1\times 10)}=C_{10}H_{10}$

The general formula of an alkane is $C_nH_{(2n+2)}$ , where n = any natural number

Here, n = 10 and it does not satisfy being an alkane

Hence, the empirical and molecular formula for the given organic compound is CH and $C_{10}H_{10}$ and it is not an alkane.

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3 years ago

PLEASE HELP ITS VERY EASY FOR OTHER PLEASE ITS A TEST DUE IN AN HOUR PLEASEEEEEEEEEE

STatiana [176]

Answer:

I think it is three times I'm not sure

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3 years ago

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A snowflake contains 2.1 10^18 molecules of water. How many moles of water does it contain?

IgorC [24]

Answer:

divide the # of molecules by avogadros number and get 3.48 x 10^-6

Explanation:

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2 years ago

How are the sensory clues from watching a fire different from the sensory clues from watching a firefly?

Mademuasel [1]

Answer:

watching a firefly is much different than watching a fire because watching a fire can make you hot and watching a firefly can make you happy

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2 years ago