People with O+ blood cannot donate their blood to negative blood types, while people with O- blood can donate to any blood type. This makes them the "universal donor." However, they can only receive O- blood.
Mendel wants to control the pollination of his pea plants because traits were not blended but they remain separate in the subsequent generations and also it is contrary to scientific opinion during his time
<u>Explanation:</u>
- Mainly, he wants to control because they were against the scientific opinion during his time.
- Mendel takes a pea plant for his experiment because it can be easily observable.
- Pea plant has seven traits and it can be pollinated by both the ways. One is self-pollination and the other is cross-pollination.
- Mendel did not know about the genes but he speculates the factors of formation in the traits.
- Mendel produces three laws, the law of dominance, the law of segregation, the law of independent assortment.
Answer:
i would go with B and E
Explanation:
by the way u could just read it
Answer:
Like bees and other pollinators, butterflies pick up pollen while they sip a flower's nectar. Once they're off to another plant, the pollen goes with them, helping to pollinate the plant species.
Explanation:
Hardy-Weinberg Equation (HW) states that following certain biological tenets or requirements, the total frequency of all homozygous dominant alleles (p) and the total frequency of all homozygous recessive alleles (q) for a gene, account for the total # of alleles for that gene in that HW population, which is 100% or 1.00 as a decimel. So in short: p + q = 1, and additionally (p+q)^2 = 1^2, or 1
So (p+q)(p+q) algebraically works out to p^2 + 2pq + q^2 = 1, where p^2 = genotype frequency of homozygous dominant individuals, 2pq = genotype frequency of heterozygous individuals, and q^2 = genotype frequency of homozygous recessive individuals.
The problem states that Ptotal = 150 individuals, H frequency (p) = 0.2, and h frequency (q) = 0.8.
So homozygous dominant individuals (HH) = p^2 = (0.2)^2 = 0.04 or 4% of 150 --> 6 people
Heterozygous individuals (Hh) = 2pq = 2(0.2)(0.8) = 0.32 or 32% of 150
--> 48 people
And homozygous recessive individuals (hh) = q^2 = (0.8)^2 = 0.64 = 64% of 150 --> 96 people
Hope that helps you to understand how to solve these types of population genetics problems!
