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Alik [6]
3 years ago
5

Will Mark brainiest

Mathematics
2 answers:
Greeley [361]3 years ago
7 0
2+3/5+1 1/4=3.85


3.85 pounds is the total weight.
slavikrds [6]3 years ago
4 0

Answer:

3.85

Step-by-step explanation:

You might be interested in
Can 3.65909090909 be expressed as a fraction whose denominator is a power of 10? Explain.
GuDViN [60]
\bf 3.659\textit{ can also be written as }\cfrac{3659}{1000}\textit{ therefore }3.6590909\overline{09}\\\\
\textit{can be written as }\cfrac{3659.0909\overline{09}}{1000}

notice above, all we did, was isolate the "recurring part" to the right of the decimal point, so the repeating 09, ended up on the right of it.

now, let's say, "x" is a variable whose value is the recurring part, therefore then

\bf \cfrac{3659.0909\overline{09}}{1000}\qquad \boxed{x=0.0909\overline{09}} \qquad \cfrac{3659+0.0909\overline{09}}{1000}\implies \cfrac{3659+x}{1000}

now, the idea behind the recurring part is that, we then, once we have it all to the right of the dot, we multiply it by some power of 10, so that it moves it "once" to the left of it, well, the recurring part is 09, is two digits, so let's multiply it by 100 then, 

\bf \begin{array}{llllllll}
100x&=&09.0909\overline{09}\\
&&9+0.0909\overline{09}\\
&&9+x
\end{array}\quad \implies 100x=9+x\implies 99x=9
\\\\\\
x=\cfrac{9}{99}\implies \boxed{x=\cfrac{1}{11}}\\\\
-------------------------------\\\\
\cfrac{3659.0909\overline{09}}{1000}\qquad \boxed{x=0.0909\overline{09}} \quad \cfrac{3659+0.0909\overline{09}}{1000}\implies \cfrac{3659+x}{1000}
\\\\\\
\cfrac{3659+\frac{1}{11}}{1000}

and you can check that in your calculator.
8 0
3 years ago
Which represents the function shown in this table?
aivan3 [116]

The answer would be c

Step-by-step explanation:

7 0
3 years ago
Which number is greatest? 2.89 times 10 Superscript negative 8 1.997 times 10 Superscript 2 8.9 times 10 Superscript negative 6
love history [14]
<h3> The greatest number is 1.997 \times 10^2</h3>

<em><u>Solution:</u></em>

<em><u>Given that the numbers are:</u></em>

2.89 \times 10^{-8}\\\\1.997 \times 10^2\\\\8.9 \times 10^{-6}\\\\5 \times 10^{-6}

We have to find the number that is greatest

Convert the numbers to decimal

2.89 \times 10^{-8} = 2.89 \times \frac{1}{10^8} =0.0000000289

1.997 \times 10^2 = 199.7

8.9\times 10^{-6}=8.9\times \frac{1}{10^6}=0.0000089

5\times 10^{-6}=5\times \frac{1}{10^6}=0.000005

We can clearly see that, 199.7 is greatest number

Thus the greatest number is 1.997 \times 10^2

3 0
3 years ago
Read 2 more answers
Type the correct answer in each box. If necessary, use /for the fraction bars
Vikentia [17]

Answer:

The experimental probability of rolling an odd number is 60%, which is 10% more than the theoretical probability.

Step-by-step explanation:

The complete question is:

Type the correct answer in each box. Use numerals instead of words. If necessary, use/ for the fraction bar(s).

A special 8-sided die is marked with the numbers 1 to 8. It is rolled 20 times with these outcomes.

3, 4, 5, 2, 7, 1, 3, 7, 2, 6, 2, 1, 7, 3, 6, 1, 8, 3, 5, 6

The experimental probability of rolling an odd number is _%, which is _% more than the theoretical probability.

Solution:

The possible outcomes of rolling an 8-sided die are:

S = {1, 2, 3, 4, 5, 6, 7, 8}

The odd numbers are:

Odd = {1, 3, 5, 7} = 4 outcomes

The theoretical probability of rolling an odd number is:

P_{T}(\text{Odd})=\farc{4}{8}=\frac{1}{2}=50\%

Now from the given 20 outcomes the odd values are:

Odd = {3, 5, 7, 1, 3, 7, 1, 7, 3, 1, 3, 5} = 12 outcomes

Compute the experimental probability of rolling an odd number as follows:

P_{E}(\text{Odd})=\frac{12}{20}=\frac{3}{5}=60\%

Thus, the experimental probability of rolling an odd number is 60%, which is 10% more than the theoretical probability.

6 0
2 years ago
Which expressions are equivalent to 23? Choose all that apply.
barxatty [35]
A
C
D
You can find the answers by dividing
7 0
3 years ago
Read 2 more answers
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