Answer:
The concentration is simply 36%
Step-by-step explanation:
In this question, we are concerned with calculating the concentration of a new mixture formed from mixing some liters of each of two vinegar variants of different concentrations.
We proceed as follows;
The concentration of the new solution will contain 12% of 13L vinegar A and 70% of 9L vinegar B
13L of vinegar A will contain 13 * 12% = 13 * 0.12 = 1.56
9L of 70% vinegar B will contain 9 * 70% = 9 * 0.7 = 6.3
Now, the new mixture has a total volume of 13 + 9 = 22L
The concentration of the new mixture will thus be;
(1.56 + 6.3)/22
= 0.357 and that’s approximately 0.36 or simply 36%
3xy(x+4)(2y+7)(xy+1) is what I got
S.F. of 9/24 = 3/8
S.F. of 14/24 = 7/12
S.F. of 10/15 = 2/3
S.F. of 10/12 = 5/6
S.F. of 18/27 = 2/3
S.F. of 10/15 = 2/3
Hope this helps!
Let's plug in the variables one by one.
6g - 2h
plug in 5 for g and 4 for h
6(5) - 2(4)
multiply
30 - 8
subtract
→ 22
20g
plug in 2 for g
20(2)
multiply
40
2(g + 1)
plug in 10 for g
2(10 + 1)
add
2(11)
multiply
→ 22
4g + 5h
plug in 1 for g and 4 for h
4(1) + 5(4)
multiply
4 + 20
add
24
Therefore, the answers that have a value of 22 are 6g - 2h and 2(g + 1)
128,147 that is in standard form
