Fluorine (F) would be least likely to form a cation out of potassium, fluorine, chlorine, and nitrogen.
- A cation is a positively charged atom (or molecule) that has lost electrons (or electrons).
- The tendency for electropositive elements to lose electrons and produce cations is greater. On the left side of the periodic table, these are often metals.
- Going down a group increases electropositivity, or the propensity to lose electrons and generate cations. and decreases across a period. In the given examples:
- Potassium, K is an alkali metal and will lose electrons readily to form a cation.
- Nitrogen (N), Fluorine (F), and chlorine (Cl) are all nonmetals that prefer to accept electrons and form anions instead. F is the most electronegative i.e. it will gain electrons and form F- rather than F+.
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Answer:
the more time you leave it to boil the water will turn to gas but if you leave it to heat for a short period of time it would probably stay the same
Explanation:
Yes it is just in the back which still makes it negative
<span>Answer is: the mass of hydrogen is 22,05 grams.
m(</span>Al(C₂H₃O₂)₃)<span> = 500 g.
M</span>(Al(C₂H₃O₂)₃) = 27 + 6 ·12 + 9 · 1 + 6 · 16 · g/mol = 204 g/mol.<span>
n</span>(Al(C₂H₃O₂)₃) = m(Al(C₂H₃O₂)₃) ÷ M(Al(C₂H₃O₂)₃).
n(Al(C₂H₃O₂)₃) = 500 g ÷ 204 g/mol.
n(Al(C₂H₃O₂)₃) = 2,45 mol.
n(Al(C₂H₃O₂)₃) : n(H) = 1 : 9.
n(H) = 22,05 mol.
m(H) = 22,05 mol · 1 g/mol
m(H) = 22,05 g.
Answer:
of the stock solution would be required.
Explanation:
Assume that a solution of volume 
contains a solute with a concentration of 
. The quantity 
of that solute in this solution would be:
.
For the solution that needs to be prepared, 
. The volume of this solution is 
. Calculate the quantity of the solute (magnesium chloride) in the required solution:
.
Rearrange the equation to find an expression of volume , given the concentration and quantity of the solute:
.
Concentration of the solute in the stock solution: 
.
Quantity of the solute required: 
.
Calculate the volume of the stock solution that would contain the required of the magnesium chloride solute:
.
