Can someone answer 5 for me please?

Hess law can help us to obtain the enthalpy of a series of reactions by summation. The missing enthalpy of this reaction is −198kJ.

According to the Hess law of constant heat summation, the enthalpy of a sequence of reactions can be obtained as the sum of the enthalpies of all the reactions.

Now looking at all the reavtion written here in order to obtain the missing enthalpy, we conclude that the missing enthalpy is −198kJ.

Learn more about enthalpy: brainly.com/question/3393755

6 0

2 years ago

Predict the sign for AS for each of the following systems: Water freezing Water evaporating Crystalline urea dissolving Assembly

djyliett [7]

Answer: 1. Water freezing : $\Delta S$ is -ve.

2. Water evaporating : $\Delta S$ is +ve.

3. Crystalline urea dissolving : $\Delta S$ is +ve.

4. Assembly of the plasma membrane from individual lipids: $\Delta S$ is -ve.

5. Assembly of a protein from individual amino acids: $\Delta S$ is -ve.

Explanation:

Entropy is defined as the measurement of degree of randomness in a system.

It is represented by symbol S and we can only measure a change in entropy which is given by $\Delta S$ .

If there is decrease in randomness , the sign for $\Delta S$ is -ve and If there is increase in randomness , the sign for $\Delta S$ is +ve.

1. Water freezing: Entropy decreases as we move from liquid state to to solid state and thus $\Delta S$ is -ve.

2. Water evaporating : Entropy increases as we move from liquid state to gaseous state and thus $\Delta S$ is +ve.

3. Crystalline urea dissolving : The molecules convert from solid and ordered state to aqueous phase and random state. Thus the entropy increases and thus $\Delta S$ is +ve.

4. Assembly of the plasma membrane from individual lipids: random lipids are associating to form a single large polymer and thus entropy decreases and thus $\Delta S$ is -ve.

5. Assembly of a protein from individual amino acids: random amino acids are associating to form a single large polymer and thus entropy decreases and thus $\Delta S$ is -ve.

5 0

2 years ago