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3 years ago

When gas particles collide with a surface

Chemistry

1 answer:

sergij07 [2.7K]3 years ago

3 0

The average kinetic energy of a collection of gas particles depends on the temperature of the gas and nothing else.

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16. If the velocity of hydrogen molecule is 5 x 10^4cm sec-¹, then its de Broglie wavelength is

Aleks04 [339]

Answer:

Correct option is B)

According to de-Broglie,

λ=mvh=6.023×10232×5×104cm/sec6.62×10−27ergsec=4×10−8cm=4Ao

5 0

2 years ago

1. When this equation is balanced, Fe + 02 -.--> Fe203, what is the

Vilka [71]

Fe + O2 → Fe2O3

After balancing the eq.

4Fe + 3O2 → 2Fe2O3

Hope this will help u mate :)

4 0

3 years ago

What mass of copper is consumed in the reaction with hydrochloric acid if 10.0 g of gas is collected?

brilliants [131]

Answer:

317 g

Explanation:

Cu + 2HCl --> CuCl2 +H2

1 : 2 1 : 1

1 mole of Cu = 63.5 g

1 mole of H2 = 2g

1 mole Cu produces = 1 mole of H2

63.5 g of Cu produces = 2 g of H2

10 g of H2 will be produced from = (63.5/2)*10 = 317 g of Copper

4 0

3 years ago

Suppose a mercury thermometer contains 3.250g of mercury and has a capillary that is 0.180mm in diameter.. How far does the merc

Helga [31]

1) You need to get volume of both temperatures by using first attached formula V= Mass/Density $V_1 = (3.250 g)/(13.596 g/(cm^3)) = .2390 cm^3
At 25 degrees C (V_2e have:

V_2 = (3.250 g)/(13.534 g/(cm^3)) = .2401 cm^3$

2) Using the second formula you get the height of 0 degree
$h = V/(pi * r^2)


h_1 =(.2390 cm^3)/(pi*(.009 cm)^2) = 939.2 cm$

(radius in cm is $(0.180 mm) / 2 * (1 cm)/(10 mm) or .009 cm$

3) Then with h1 you can easily get the height of 25 degrees
$h_2 =(.2401 cm^3)/(pi*(.009 cm)^2) = 943.5 cm$

Subtract 943.5 cm - 939.2 cm, and obtain a rise in mercury height of 4.3 cm

5 0

3 years ago

Read 2 more answers

Cycloheptatrienone is stable, but cyclopentadienone is so reactive that it can't be isolated. Taking into account the polarity o

Lorico [155]

Answer and Explanation:

The resonance contributor in cyclopentadienone (as shown in the attachment below) results into the compound having a positive charge on the carbonyl group, C=O which accounts for a highly reactive anti-aromatic 4π system. And this illustrates the reason for its instability.

3 0

3 years ago