1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Mice21 [21]
3 years ago
11

When gas particles collide with a surface

Chemistry
1 answer:
sergij07 [2.7K]3 years ago
3 0
The average kinetic energy of a collection of gas particles depends on the temperature of the gas and nothing else.
You might be interested in
Which tool should Darla and Rob use to measure the force that pulls a car down the map
svetoff [14.1K]

Answer:

C. A Spring Scale

Explanation:

Using process of elimination, we can quickly decide that a stopwatch and a ruler will not be useful in measuring the force. This leaves us with either the spring scale or a balance scale. A balance scale is used to compare two weights, so this is eliminated. That leaves us with a spring scale. This is because we can attached the spring scale to the car and when we let it go, we can record the force. I hope this helps!

5 0
2 years ago
What are some example of nuclear acids
vladimir1956 [14]
First of all, it is a nucleic acid, not nuclear acid.

Examples are DNA and RNA( Deoxyribonucleic Acid and Ribonucleic Acid)
3 0
3 years ago
Using the van der Waals equation, determine the pressure exerted by 4.30 mol Ar in 3.6 L at 325K.
Vika [28.1K]

Answer:

37.7 atm

Explanation:

Using the relation;

(P + an^2/V^2) (V - nb) = nRT

(P + an^2/V^2) = nRT/(V - nb)

a = 0.0341 atm dm^2 Mol^2

b = 0.0237 dm/mol

P = nRT/(V - nb) - an^2/V^2

P = [4.3 * 0.082 * 325 / (3.6 - (4.3 * 0.0237))] - (0.0341 * (4.3^2))/(3.6^2)

P = 114.595/(3.498) - 0.0487

P = 37.7 atm

5 0
3 years ago
Clay and organic matter generally have higher capacity for retaining nutrients than silt and sand.
Svetlanka [38]
The answer is false  because clay have more silt and sand
 
5 0
3 years ago
Read 2 more answers
What is the E°cell for the cell represented by the combination of the following half-reactions? ClO4–(aq) + 8H+(aq) + 8e– Cl–(aq
Vinvika [58]

Answer:

The E°cell for the cell represented by the combination of the given half-reactions is 0.398 V

Explanation:

Oxide-reduction reactions, also called redox, involve the transfer or transfer of electrons between two or more chemical species. In these reactions two substances interact: the reducing agent and the oxidizing agent.

The gain of electrons is called reduction and the loss of electrons oxidation. That is to say, there is oxidation whenever an atom or group of atoms loses electrons (or increases its positive charges) and in the reduction an atom or group of atoms gains electrons, increasing its negative charges or decreasing the positive ones.

The species that supplies electrons is the reducing agent (that is, it is that species that oxidizes, yielding electrons and increasing its positive charge, or decreasing the negative one causing the reduction of the other species) and the one that gains them is the oxidizing agent ( that is, it is that species that is reduced, capturing electrons and increasing its negative charge, or decreasing its positive charge, causing oxidation of the other species).

This is the type of reaction that occurs in this case.

ClO₄⁻(aq) + 8 H⁺ (aq) + 8 e⁻ ⇔ Cl⁻ (aq) + 4 H₂O(l) E° = 1.389 V

VO₂⁺(aq) + 2 H⁺(aq) + e⁻ ⇔ VO⁺(aq) + H₂O(l) E° = 0.991 V

In this case both are written as reductions, and their E ° values ​​as well. The species that has the greatest potential for reduction will be the species that will be reduced, that is, it will be the oxidizing agent. In this case, it will be the first half-reaction expressed.  Therefore, to obtain a reaction, the second semi-reaction must be reversed to be an oxidation, maintaining its constant value. Then:

Reduction: ClO₄⁻(aq) + 8 H⁺ (aq) + 8 e⁻ ⇔ Cl⁻ (aq) + 4 H₂O(l) E° = 1.389 V

Oxidation: VO⁺(aq) + H₂O(l) ⇔ VO₂⁺(aq) + 2 H⁺(aq) + e⁻ E° = 0.991 V

<em>E°cell=Ereduction - Eoxidation</em>

E°cell=1.389 V - 0.991 V

<em>E°cell=0.398 V</em>

Then <u><em>the E°cell for the cell represented by the combination of the given half-reactions is 0.398 V.</em></u>

Another way of thinking is that, by inverting the second semi-reaction to be an oxidation, the value of E ° is reversed in the sign, unlike the previous case in which it was constant. Then:

Reduction: ClO₄⁻(aq) + 8 H⁺ (aq) + 8 e⁻ ⇔ Cl⁻ (aq) + 4 H₂O(l) E° = 1.389 V

Oxidation: VO⁺(aq) + H₂O(l) ⇔ VO₂⁺(aq) + 2 H⁺(aq) + e⁻ E° = -0.991 V

In this case:

E°cell=Ereduction + Eoxidation=

E°cell=1.389 V + (-0.991 V)=1.389 V-0.991 V

<em>E°cell=0.398 V</em>

Note that the result obtained is the same. This indicates that either of the two ways proposed is correct, and you will use the one that is most comfortable for you.

4 0
3 years ago
Other questions:
  • Which symbol in a chemical equation separates the reactants from the products?​
    9·2 answers
  • The compound mgso4, epsom salts, is used to soothe sore feet and muscles. how many grams will you need to prepare a bath contain
    11·2 answers
  • A Venn diagram is used to compare and contrast different topics. The items that are unique to each topic are represented in the
    7·2 answers
  • Match each number to how it would appear in scientific notation.
    7·2 answers
  • Calculate the molar mass of Cr4(P2O7)
    5·1 answer
  • How many formula units are in 5.33 moles of cucl2​
    14·1 answer
  • A chemist carefully measures the amount of heat needed to raise the temperature of a 894.0g sample of a pure substance from to −
    5·1 answer
  • Which star is the dimmest HELP PLEASE
    14·2 answers
  • 09:10 .l . KS
    7·1 answer
  • During chemical cycling, inorganic nutrients are typically returned to the soil by:.
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!