I’m almost 100% sure it’s D, because environmental factors can induce a mutation. A mutation can be beneficial but it can also be harmful, so it’s neither B or C, and it can’t be A, because mutations can come from natural selection as well. So it’s D.
Antibodies, a small amount of the germ
Answer:
The mother can carry a full-term baby with A blood type because the mother's blood does not mix with the baby's blood, so the mother's immune system does not activate attacking the baby.
Explanation:
The reason why a mother with B blood type and A antibodies in her system can carry a full-term pregnancy is thanks to the placenta. The placenta is a shared organ between the mother and the baby. Its function is to protect the baby and produce the necessary exchanges of nutrients and wastes between the maternal blood and the baby's blood. As the two types of blood are separated, and they never get in contact during pregnancy, the immune system of the mother does not recognize the baby as a treat. The mother can have A antibodies in her plasma due to a previous pregnancy where during delivery, the two types of blood mixed, also it can be due to any contact with the A blood type. When the foreign blood enters the body, the immune system forms antibodies for it.
Can you reright it in English?
The answer is false. To explain further, let G have vertices
{v1, v2, v3, v4}, with ends between each pair of vertices, and with the mass on
the edge from vi to vj equal to I + j. Then each tree has a bottle neck edge mass
of as a minimum of 5, so the tree containing of a track through vertices v3, v2,
v1,v4 is a least bottleneck tree. It is not a least spanning tree, though, subsequently
its total mass is greater than that of the tree with edges from v1 to every
single vertex.