3.3.1: A roof has a pitch of 15°, as shown. If the width of the roof, WY, is 28 ft,
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The area of any circle is equal to 
, where r is the radius.
We know that the diameter is 12. The radius is always half of the diameter, so the radius of our circle must be 6.
Substitute 6 for r in our equation and simplify.
π6² = π6×6 = 36π in²
We know that the diameter is 12. The radius is always half of the diameter, so the radius of our circle must be 6.
Substitute 6 for r in our equation and simplify.
π6² = π6×6 = 36π in²