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Nitella [24]
3 years ago
15

Zn(s) + 2HCl(aq) → ZnCl2(aq) + H2(g) If you have 4 moles of zinc and 4 moles of hydrochloric acid, which of these would be the l

imiting reactant? A) zinc B) hydrogen gas C) zinc chloride D) hydrochloric acid
Chemistry
1 answer:
Y_Kistochka [10]3 years ago
8 0

Answer:

D) hydrochloric acid.

Explanation:

  • The balanced equation for the mentioned reaction is:

<em>Zn(s) + 2HCl(aq) → ZnCl₂(aq) + H₂(g),</em>

<em></em>

It is clear that 1.0 moles of Zn react with 2.0 moles of HCl to produce 1.0 moles of ZnCl₂ and 1.0 mole of H₂.

  • From stichiometry; Zn reacts with HCl with (1: 2) molar ratio.

<em>∴ 2.0 mol of Zn (the remaining 2.0 mol is in excess) react completely with 4.0 mol of HCl with (1: 2) molar ratio.</em>

<em />

So,

the limiting reactant is HCl and the excess reactant is Zn.

<em>Thus, the right choice is: D) hydrochloric acid.</em>

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Explanation:

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Computation:

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Acetic acid (HC2H3O2, Ka=1.8x10^-5) is a weak acid. Calculate the pH of an aqueous solution of .25M acetic acid.
tensa zangetsu [6.8K]

Answer: The pH of an aqueous solution of .25M acetic acid is 2.7

Explanation:

HC_2H_3O_2\rightarrow H^+C_2H_3O_2^-

 cM              0             0

c-c\alpha        c\alpha          c\alpha  

So dissociation constant will be:

K_a=\frac{(c\alpha)^{2}}{c-c\alpha}

Give c= 0.25 M and \alpha = ?

K_a=1.8\times 10^{-5}

Putting in the values we get:

1.8\times 10^{-5}=\frac{(0.25\times \alpha)^2}{(0.25-0.25\times \alpha)}

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Also pH=-log[H^+]

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