Zn(s) + 2HCl(aq) → ZnCl2(aq) + H2(g) If you have 4 moles of zinc and 4 moles of hydrochloric acid, which of these would be the l
imiting reactant? A) zinc B) hydrogen gas C) zinc chloride D) hydrochloric acid
1 answer:
Answer:
D) hydrochloric acid.
Explanation:
- The balanced equation for the mentioned reaction is:
<em>Zn(s) + 2HCl(aq) → ZnCl₂(aq) + H₂(g),</em>
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It is clear that 1.0 moles of Zn react with 2.0 moles of HCl to produce 1.0 moles of ZnCl₂ and 1.0 mole of H₂.
- From stichiometry; Zn reacts with HCl with (1: 2) molar ratio.
<em>∴ 2.0 mol of Zn (the remaining 2.0 mol is in excess) react completely with 4.0 mol of HCl with (1: 2) molar ratio.</em>
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So,
the limiting reactant is HCl and the excess reactant is Zn.
<em>Thus, the right choice is: D) hydrochloric acid.</em>
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