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Nadusha1986 [10]
3 years ago
5

Which of the following processes takes place inside the sun

Chemistry
2 answers:
HACTEHA [7]3 years ago
8 0
Heat and thermal and mechanical occurs hope this helps
AnnyKZ [126]3 years ago
8 0

Answer:

The nuclear fusion reactor.The nuclear reaction that takes place within the Sun, which is, for all intents and purposes, a giant nuclear fusion reactor, is the fusion of two isotopes of hydrogen, deuterium ( 21H ) and tritium ( 31H ), into a nucleus of helium-4 ( 42He ), containing two electrons, orbiting a nucleus of two protons, and two.

Explanation:

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When a hydrogen atom makes the transition from the second excited state to the ground state (at -13.6 eV) the energy of the phot
viktelen [127]

Answer : The energy of the photon emitted is, -12.1 eV

Explanation :

First we have to calculate the 'n^{th}' orbit of hydrogen atom.

Formula used :

E_n=-13.6\times \frac{Z^2}{n^2}ev

where,

E_n = energy of n^{th} orbit

n = number of orbit

Z = atomic number  of hydrogen atom = 1

Energy of n = 1 in an hydrogen atom:

E_1=-13.6\times \frac{1^2}{1^2}eV=-13.6eV

Energy of n = 2 in an hydrogen atom:

E_3=-13.6\times \frac{1^2}{3^2}eV=-1.51eV

Energy change transition from n = 1 to n = 3 occurs.

Let energy change be E.

E=E_-E_3=(-13.6eV)-(-1.51eV)=-12.1eV

The negative sign indicates that energy of the photon emitted.

Thus, the energy of the photon emitted is, -12.1 eV

3 0
2 years ago
Which characteristic of living organisms is described by the following definition? "The ability
saw5 [17]
3 I don’t know but it may be movement
3 0
3 years ago
How much work (in J) is involved in a chemical reaction if the volume decreases from 5.00 to 1.48 L against a constant pressure
Dahasolnce [82]
Given:
ΔV = 5 - 1.48 L = 3.52 L = 0.00352 m³, th chane in volume
p = 0.818 atm = 0.819*101325 Pa = 82985.2 Pa

By definition, the work done is
W = \int pdV = (82985.2 \,  \frac{N}{m^{2}} )*(0.00352 \, m^{3}) = 292.1 \, J

Answer: 292.1 J
5 0
3 years ago
Type the correct answer in each box.
Luba_88 [7]

Answer:  The weight of the object on earth =441N

Weight of the object on moon = 72N

6 0
3 years ago
It takes 2,267 joules of heat to raise the temperature of a 44.5 gram sample of a metal from 33.9°C to 288.3°C. What is the heat
ehidna [41]

Answer:

\boxed{\text{0.200 J$^{\circ}$C$^{-1}$g$^{-1}$}}}

Explanation:

The formula for the amount heat q absorbed by a substance is

q = mcΔT

where

 m = the mass of the substance

  C = the specific heat capacity of the material

ΔT = the temperature change

Data:

 q = 2267 J

m = 44.5 g

T₁ = 33.9 °C

T₂ = 288.3 °C

Calculations:

ΔT = (288.3 - 33.9) °C = 254.4 °C

\begin{array}{rcl}2267 & = & 44.5 \times C \times 254.4\\2267 & = & 11 180C\\C& = & \dfrac{2267}{11180}\\\\& = & \textbf{0.200 J$^{\circ}$C$^{-1}$g$^{-1}$}\\\end{array}

\text{The specific heat capacity of the metal is \boxed{\textbf{0.200 J$^{\circ}$C$^{-1}$g$^{-1}$}}}

5 0
3 years ago
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