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Nina [5.8K]
3 years ago
7

Water is being pumped from the bottom of a well 150 feet deep at a rate of 200 gal/hour into a vented storage tank 30 feet above

the ground. To prevent freezing in the winter, a small heater puts 30,000 BTU/hour into the water during its transfer from the well to the storage tank. Heat is lost from the whole system at a constant rate of 25,000 BTU/hr. What is the rise or fall in the temperature of the water as it enters the storage tank, if the well ware is at 35°F? A 2 HP pump is being used to pump the water. The pump efficiency is 55 percent. Evaluate any properties of water at 35°F.
Chemistry
1 answer:
KengaRu [80]3 years ago
3 0

Explanation:

As the given data is as follows.

        Height, H = 150 feet

 Heat gain = 30,000 BTU/hr,  and  Heat loss = 25000 BTU/hr

  m = mass of water heated = 700 gallons = 5810 lbs

C_{p} is the heat capacity of water = 1 BTU/lb ^{o}F (given)

      \Delta T = temperature difference = 120^{o}F - 35^{o}F

Heat energy required to heat 700 gal can be calculated as follows:

    Heat Required = 5810 lbs \times 1 BTU/lb^{o}F \times (120^{o}F - 35^{o}F)

Thus, water rises till 120^{o}F.

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Convert the pressure 525.4 torr to kPa.
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Option A. 70.0 KPa.

Explanation:

Data obtained from the question include:

Pressure (torr) = 525.4 torr

Pressure (kPa) =?

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At 700 K, the reaction 2SO2(g) + O2(g) <====> 2SO3(g) has the equilibrium constant Kc = 4.3 x 106. At a certain instant, f
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Answer:

The system is not in equilibrium and will evolve left to right to reach equilibrium.

Explanation:

The reaction quotient Qc is defined for a generic reaction:

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Q=\frac{[C]^{c} *[D]^{d} }{[A]^{a}*[B]^{b}  }

where the concentrations are not those of equilibrium, but other given concentrations

Chemical Equilibrium is the state in which the direct and indirect reaction have the same speed and is represented by a constant Kc, which for a generic reaction as shown above, is defined:

Kc=\frac{[C]^{c} *[D]^{d} }{[A]^{a}*[B]^{b}  }

where the concentrations are those of equilibrium.

This constant is equal to the multiplication of the concentrations of the products raised to their stoichiometric coefficients divided by the multiplication of the concentrations of the reactants also raised to their stoichiometric coefficients.

Comparing Qc with Kc allows to find out the status and evolution of the system:

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  • If the reaction quotient is greater than the equilibrium constant, Qc> Kc, the system is not in equilibrium. In this case the direct reaction predominates and there will be more product present than what is obtained at equilibrium. Therefore, this product is used to promote the reverse reaction and reach equilibrium. The system will then evolve to the left to increase the reagent concentration.
  • If the reaction quotient is less than the equilibrium constant, Qc <Kc, the system is not in equilibrium. The concentration of the reagents is higher than it would be at equilibrium, so the direct reaction predominates. Thus, the system will evolve to the right to increase the concentration of products.

In this case:

Q=\frac{[So_{3}] ^{2} }{[SO_{2} ]^{2}* [O_{2}] }

Q=\frac{10^{2} }{0.10^{2} *0.10}

Q=100,000

100,000 < 4,300,000 (4.3*10⁶)

Q < Kc

<u><em> The system is not in equilibrium and will evolve left to right to reach equilibrium.</em></u>

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Hi there!

A mole is a type of unit measurement for an amount of a substance like in your cast, salt.

One mole of salt will be the equivalent to 58 grams

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