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Andru [333]
3 years ago
7

The substances present before a chemical reaction takes place are called?

Chemistry
2 answers:
andrew11 [14]3 years ago
5 0
The substances present before the reaction are the reactants.  (As the reaction goes through, the substances that are produced are called the products of the reaction).
jeka57 [31]3 years ago
5 0
Reactants. just did the penn foster exam
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500.0 mL of a gas is collected at 745.0 mm Hg. what what will the volume be at standard pressure
Irina-Kira [14]
This is an application of Boyle's law:
P₁V₁ = P₂V₂. we don't have to convert volume and pressure to standard forms. we can even use the pressure with mmHg
1 atm = 760 mmHg 
V₂ = P₁V₁ / P₂ = 745 x 500 / 760 = 490 ml
Note that here we assume constant temperature
6 0
3 years ago
For lunch, a patient consumed 3 oz of skinless chicken, 3 oz of broccoli, 1 medium apple, and 1 cup of nonfat milk (see Table 3.
Volgvan

Lunch of a patient has 3 oz skinless chicken, 3 oz of broccoli, 1 medium apple, and 1 cup of nonfat milk

Energy content of 3 oz skinless chicken is = 110 kcal

Energy content of 3 oz broccoli = 30 kcal

Energy content of 1 medium apple = 60 kcal

Energy content of 1 cup non-fat milk = 90 kcal

So the kilocalories of energy patient obtained from lunch

                   = 110 kcal+ 30 kcal + 60 kcal + 90 kcal = 290 kcal


3 0
3 years ago
Describe the evidence of changes in organisms in the Cambrian Era that are reflected in the fossil record.​
UkoKoshka [18]

Answer:

Morphology and phylogenetics revealed by fossils. Perhaps the strongest evidence to support the Cambrian evolutionary explosion of animal forms is the first clear appearance, in the Early Cambrian, of skeletal fossils representing members of many marine bilaterian animal phyla

Explanation:

also pls vote brainliest <3 :)))

3 0
3 years ago
What is the density of an object with volume of 5.36 mL and mass of 58.3
choli [55]

Answer:

option d is correct

Explanation:

8 0
3 years ago
Match the following with their correct molecular weight. 2-butanone Propyl acetate 4-methyl-2-pentanone Butyl acetate Methanol E
Hatshy [7]

Answer:

2-butanone = 72.11 g/mol (option F)

Propyl acetate  = 102.13 g/mol (option C)

4-methyl-2-pentanone = 100.16 g/mol (option D)

Butyl acetate = 116.16 g/mol (option B)

Methanol = 32.04 g/mol (option E)

Ethanol  = 46.07 g/mol (option A)

Explanation:

Step 1: Data given

Molar mass of C = 12.01 g/mol

Molar mass of H = 1.01 g/mol

Molar mass of O = 16.00 g/mol

Step 2:

2-butanone = C4H8O

⇒ 4*12.01 + 8*1.01 + 16.00 = 72.11 g/mol (option F)

Propyl acetate = C5H10O2

⇒ 5*12.01 + 10*1.01 + 2*16.00 = 102.13 g/mol (option C)

4-methyl-2-pentanone = C6H12O

⇒ 6*12.01 + 12*1.01 + 16.00 = 100.16 g/mol (option D)

Butyl acetate = C6H12O2

⇒ 6*12.01 + 12*1.01 + 2*16.00 = 116.16 g/mol (option B)

Methanol = CH3OH = CH4O

⇒ 12.01 + 4*1.01 + 16.00 = 32.04 g/mol (option E)

Ethanol = C2H5OH = C2H6O

⇒ 2*12.01 + 6*1.01 + 16.00 = 46.07 g/mol (option A)

4 0
3 years ago
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