Answer:
heating makes the alcohol molecules of the liquid move faster.
When comparing single bonds between atoms of comparable types, the stronger the bond is, the bigger the atom, the weaker it is.
The length of the X-H bond lengthens while the strength of the bond shortens with increasing halogen size (F-H strongest, I-H weakest). When comparing single bonds between atoms of similar sorts, the larger the atom, the weaker the bond. It can be explained by the fact that less energy is required to break the bond the bigger the atom's atomic size. The force of attraction from the nucleus to the outermost orbit will be less for iodine since it has a larger atom than the other elements in the group.
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Answer:
Explanation:
<u>1) Data:</u>
a) V = 500.0 ml = 0.500 liter
b) M = 0.100
c) mass = ?
<u>2) Formulae:</u>
a) Molarity: M = n / V
b) Number of moles: n = mass in grams / molar mass
<u>3) Solution</u>
a) M = n / V ⇒ n = M × V = 0.1000 M × 0.500 liter = 0.0500 mol
b) molar mass NaCl = 58.443 g/mol
c) mass = n × molar mass = 0.0500 mol × 58.443 g/mol = 2.92 g
Answer: 2.92 g
Answer:81.6%
Explanation:
Mass of CaCO3=4.010 g
Molar mass of CaCO3= 40+12+(16×3) = 100 g/mol.
Recall: number of moles(n)= mass÷ molar mass.
n=4.010÷100 = 0.0401 mol.
Molar mass of CaCl2 = 40+71= 111 g/mol.
Number of mol of CaCl2 = 5.455÷111= 0.04914 g/mol.
Mass of CaCl2 = 0.0401 × 111 = 4.4511 g of CaCl2.
Percent by mass of CaCl2 = (4.4511÷5.455) × 100
= 0.815967 ×100 = 81.5967%
Approximately; 81.6%.
Answer:
1) the oxidation state of the metal is +2
2) there are four d electrons
3) metal valence electrons =4 ligand valence electrons= 18
4) sp^3d^2
5) octahedral geometry
Explanation:
[Cr(H2O)6]2+ is an octahedral complex. Octahedral complexes are known to have the metal ion in sp^3d^2 hybridization state. Since there are six ligands each bonding to the central metal ion, there are eighteen ligand valence electrons and four valence electrons from the metal present in the high spin complex.
The crystal field of high spin and low spin octahedral for a d4 ion is shown in the image attached.
