Answer:
2 moles of NO2 would be produced.
Explanation:
Here, you will have to do a mole to mole ratio.
2 moles NO x (2 moles NO2 / 2 moles NO)
= 2 moles NO2
Answer:
88.50 %
The balance chemical equation is as follow,
2 H₂ + O₂ → 2 H₂O
Step 1: Find the limiting reactant;
According to eq.
4.032 g (2 mole) H₂ reacts with = 32 g (1 mole) of O₂
So,
11 g of H₂ will react with = X g of O₂
Solving for X,
X = (11 g × 32 g) ÷ 4.032 g
X = 87.301 g of O₂
Therefore, H₂ is the limiting reactant as O₂ is present in excess.
Step 2: Calculating %age Yield;
According to eq.
4.032 g (2 mole) H₂ produces = 36.032 g (1 mole) of H₂O
So,
11 g of H₂ will react with = X g of H₂O
Solving for X,
X = (11 g × 36.032 g) ÷ 4.032 g
X = 98.301 g of H₂O
So,
Actual Yield = 87 g
Theoretical Yield = 98.301 g
Using formula = Actual Yield / Theoretical Yield × 100
= 87 g / 98.301 × 100
= 88.50 %
percentage error=difference/actual value x 100
=0.534/13.0 x 100
=4.11%
Answer:
120g
Explanation:
Based on the reaction, when 1 mole of propane and 5 moles of oxygen react, 3 moles of CO2 and 4 moles of H2O are produced. The ratio of production is 3 moles of CO2 per 4 moles of H2O.
Thus, we need to convert mass of water to moles using its molar mass:
Moles H2O (Molar mass: 18g/mol):
63g H2O * (1mol / 18g) = 3.5 moles H2O
Converting to moles of CO2:
3.5 moles H2O * (3 moles CO2 / 4 moles H2O) = 2.625 moles CO2
Mass CO2 (Molar mass: 44g/mol):
2.625 moles CO2 * (44g / mol) = 115.5g of CO2 are released
<h3>120g
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