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AlekseyPX
2 years ago
8

Occurs when the membrane surrounds a large substance and engulfs it.

Chemistry
1 answer:
Sloan [31]2 years ago
5 0
A the answer is A CAUSE IM A DIFFERENT BREED
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What elements comprise the largest portion of Earth's atmosphere?​
Mrrafil [7]

Answer:

Nitrogen and Oxygen make up 99% of the Earths atmosphere. Then Argon makes up the rest of the atmosphere.

3 0
3 years ago
Hydrogen bonds form between neighboring water molecules because of:
12345 [234]
*A & B*

Answers A & B are not possible, as Hydrogen “bonds” are intermolecular forces and do not actually involve transfer or sharing of electrons.

*C & D*

Viscosity and surface tension are not the answer as they are not specific enough to the question.

*E*

Polarity of water molecules is the correct answer, as water molecules are highly polar. The partial positive of the Hydrogen on one water molecule is highly attracted to the partial negative of the Oxygen (due to its lone pairs) on another water molecule.
4 0
3 years ago
The mass of sample A is 100.0 g, then removed it from a graduated
yan [13]

Answer: 25g/ml

Explanation:

Density = 100.0g/ 4.0mL = 25g/mL

3 0
3 years ago
To convert from mass of A to moles of B in a stoichiometry problem, the following steps are followed:
taurus [48]

Answer:

b. mass A → moles A → moles B

Explanation:

hope this helps

4 0
3 years ago
A student determines the molar mass of acetone, CH3COCH3, by the method used in this experiment. She found that the equilibrium
Alexandra [31]

Answer:

(a). 4°C, (b). 2.4M, (c). 11.1 g, (d). 89.01 g, (e). 139.2 g and (f). 58 g/mol.

Explanation:

Without mincing words let's dive straight into the solution to the question.

(a). The freezing point depression can be Determine by subtracting the value of the initial temperature from the final temperature. Therefore;

The freezing point depression = [ 1 - (-3)]° C = 4°C.

(b). The molality can be Determine by using the formula below;

Molality = the number of moles found in the solute/ solvent's weight(kg).

Molality = ( 11.1 / 58) × (1000)/ ( 90.4 - 11.1) = 2.4 M.

(c). The mass of acetone that was in the decanted solution = 11.1 g.

(d). The mass of water that was in the decanted solution = 89.01 g.

(e). 2.4 = x/ 58 × (1000/1000).

x = 2.4 × 58 = 139.2 g.

(f). The molar mass of acetone = (12) + (1 × 3) + 12 + 16 + 12 + (1 x 3) = 58 g/mol.

7 0
3 years ago
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