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Neporo4naja [7]
3 years ago
14

The pka of hypochlorous acid is 7.530. a 52.0 ml solution of 0.149 m sodium hypochlorite (naocl) is titrated with 0.293 m hcl. c

alculate the ph of the solution
Chemistry
1 answer:
gavmur [86]3 years ago
8 0

Answer:

The pH of the buffer solution is 7.236

Explanation:

Henderson - Hasselbalch equation of a buffer solution consisting of a weak acid and its conjugate base is given as:

pH=pK_a+log(\frac{[conjugate base]}{[weak acid]})

The hypochlorous acid (HCIO),  is the weak acid  and the conjugate base the  hypochlorite anion (ClO⁻) is the conjugate base.

The dissociation of the salt is given by:

NaOCl(aq)  ⇒  Na⁺(aq) + ClO⁻(aq)

The salt dissociate at a ratio of 1:1

Substituting values to get:

pH=pK_a+log(\frac{[conjugate base]}{[weak acid]})\\pH=7.53+log(\frac{0.149M}{0.293M})\\pH=7.53-0.2937\\pH=7.236

The pH of the buffer solution is 7.236

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