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Mila [183]
2 years ago
12

Which of the following is the correct calculation for determining the density of an object with a mass of 54 g and a volume of 6

mL?
Chemistry
1 answer:
RSB [31]2 years ago
3 0

Answer:

\rho =9g/mL

Explanation:

Hello,

In this case, since the density is computed via the division of the mass by the volume:

\rho =\frac{m}{V}

For the given mass of 54 g and volume of 6 mL, the density turns out:

\rho =\frac{54g}{6mL}\\ \\\rho =9g/mL

Best regards.

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Determine the [OH−] , Ph, and POH of a solution with a [H+] of 0. 00017 m at 25 °C.
tino4ka555 [31]

Main Answer:

Given

pH = -log[H+]

= -log[0.00017]

= 3.769

We know that

pW = pH + pOH

and pW =14

pOH = 14-pH

=14-3.769

=10.231

According to the definition

pOH = -log[OH-]

10.231 = log[OH-]-1

[OH-]= 5.87 x 10-11

Explanation:

What is pH?

pH is defined as the concentration of H+ ion in the solution. If the pH value is less than 7, then the solution will be acidic. If the pH value is greater than 7, then the solution will be basic.

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4 0
1 year ago
The volume (in L) that would be occupied by 5.00 mols of 02 at STP is
crimeas [40]

Answer : The volume of oxygen at STP is 112.0665 L

Solution : Given,

The number of moles of O_2 = 5 moles

At STP, the temperature is 273 K and pressure is 1 atm.

Using ideal gas law equation :

PV=nRT

where,

P = pressure of gas

V = volume of gas

n = the number of moles

T = temperature of gas

R = gas constant = 0.0821 L atm/mole K   (Given)

By rearranging the above ideal gas law equation, we get

V=\frac{nRT}{P}

Now put all the given values in this expression, we get the value of volume.

V=\frac{(5moles)\times (0.0821Latm/moleK)\times (273K)}{1atm}=112.0665L

Therefore, the volume of oxygen at STP is 112.0665 L

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Morphine is a well known pain killer but is highly addictive. The lethal dose of morphine varies from person to person based on
Aliun [14]

Answer:

0.252 milimoles

Explanation:

To convert mass of a substance to moles it is necessary to use the molar mass of the substance.

The formula of morphine is C₁₇H₁₉NO₃, thus, its molar mass is:

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H: 19*1.01g/mol = 19.19g/mol

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O: 3*16g/mol = 48g/mol.

204.17 + 19.19 + 14 + 16 = <em>285.36g/mol</em>

Thus, moles of 71.891 mg = 0.071891g:

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As 1 mole = 1000 milimoles:

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