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ikadub [295]
3 years ago
10

4Na + O2 --> 2Na20 If 4 moles of Na react completely, how many moles of Na2O form?

Chemistry
2 answers:
Olegator [25]3 years ago
8 0

Answer:

Rebecca, as I used to tell my chemistry students, the key to ANY stoichiometry problem is to first write the balanced equation. Even if you think you can solve the problem in your head. In your question, you know your two reactants and you know your product. Your question itself provides the unbalanced equation:

H2 + O2 → H2O

But the oxygen atoms come in packages of two. Currently the there are two oxygen atoms on the left and only one on the right. Let’s fix that:

H2 + O2 → 2 H2O

So we have the same number of oxygen atoms left and right, but now there are not enough hydrogen atoms on the left. Let’s fix that as well:

2 H2 + O2 → 2 H2O

Our equation is balanced! As sometimes happens, the answer to the question is staring us in the face. Two hydrogen molecules would give us two molecules of water. Two dozen hydrogen molecules would give us two dozen molecules of water. A mole is a number like a dozen only much bigger. Two moles of hydrogen molecules will give us two moles of water molecules.

Explanation:

hope this helps

Sati [7]3 years ago
5 0
2 moles of Na2O are produced.

4 moles of Na react with 1 mole of O.
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What is the percent composition of hydrogen in a compound if the mass of the initial compound is 276 gram and the mass of collec
mariarad [96]

Answer: The percentage composition of hydrogen in the given compound is 15%.

Explanation:

To calculate the percentage composition of hydrogen in a compound, we use the formula:

\%\text{ composition of hydrogen}=\frac{\text{Mass of hydrogen}}{\text{Mass of compound}}\times 100

Where,

Mass of hydrogen = 41.4 grams

Mass of compound = 276 grams

Putting values in above equation, we get:

\%\text{ composition of hydrogen}=\frac{41.4g}{276}{\times 100

Percentage composition of hydrogen in a given compound = 15%

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Addition of 6 m hcl to which substance will not result in gas evolution?
saul85 [17]

There is no gaseous product when NaNO3 reacts with 6M HCl.

We must note that gas evolution is one of the signs that a chemical reaction has taken place. Hence, we must consider the options and look out for an option in which reaction with HCl does not lead to a gaseous product. This is the option that does not lead to evolution of a gas.

Let us consider the reaction; NaNO3(s) + HCl(aq) ---> NaCl(s) + HNO3(aq), there is no gaseous product hence NaNO3 does not result in gas evolution upon addition of 6M HCl.

Missing parts;

Addition of 6 M HCl to which substance will NOT result in gas evolution?

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(B) Zn

(C) K2CO3

(D) NaNO3

Learn more about evolution of gas: brainly.com/question/2186340

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