Perpendicular distance i believe
The first five terms of the recursively defined sequence are 6, 12, 48, 768, 196608
For given question,
We have been given the recursive formula of a sequence.

Also, the first term of the sequence is,
a1 = 6
Substitute k = 1 in given recursive formula.
⇒ 
⇒ a2 = 1/3 (6)²
⇒ a2 = (1/3) × 36
⇒ a2 = 12
Substitute k = 2 in given recursive formula.
⇒ 
⇒ a3 = (1/3) × (12)²
⇒ a3 = (1/3) × 144
⇒ a3 = 48
Substitute k = 3 in given recursive formula.
⇒ 
⇒ a4 = (1/3) × (48)²
⇒ a4 = (1/3) × 2304
⇒ a4 = 768
Substitute k = 4 in given recursive formula.
⇒ 
⇒ a5 = (1/3) × (768)²
⇒ a5 = (1/3) × 589824
⇒ a5 = 196608
Therefore, the first five terms of the recursively defined sequence are 6, 12, 48, 768, 196608
Learn more about the recursive formula of sequence here:
brainly.com/question/14457800
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Answer:
.9 or 90%
.1 or 10%
Step-by-step explanation:
E= Exam
P=Paper
E= .71
P= .45
E∩P=.26
A.) E∪P=?
E∪P= E+P-E∩P
.71+.45-.26= .9
B.) E'∩P' = (E∪P)'
(E∪P)' = 1-.9 = .1
It looks like only A and B, but could be trick question?
Answer:
No, x can't equal zero.
Step-by-step explanation:
substitute x for zero. now the equation says 4+0+2>8
4+2 is 6 so 6 < 8. 6 is less than 8 not greater, therefore x can't be zero