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gavmur [86]
3 years ago
7

What is the absolute pressure at a depth of 9.05 m below the surface of a deep lake? Assume atmospheric pressure is 1.01 × 10 5

Pa .
Physics
1 answer:
Arte-miy333 [17]3 years ago
8 0

Answer:

1.89 x 10⁵ Pa

Explanation:

given,

depth of the lake = 9.05 m

atmospheric pressure = 1.01 × 10⁵ Pa

absolute pressure = ?

we know,

Absolute pressure = atmospheric pressure + gauge pressure

Absolute pressure = 1.01 × 10⁵ Pa + ρgh

Absolute pressure = 1.01 × 10⁵ Pa + 1000 x 9.8 x 9.05

Absolute pressure = 1.89 x 10⁵ Pa

hence, absolute pressure is equal to 1.89 x 10⁵ Pa

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             T- fr = Ma

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we write the system of equations

             T - fr = M a

             mg - T = m a

we add and resolved

             mg-  μ Mg = (M + m) a

             a = g \ \frac{m - \mu M}{m+M}

             a = 9.8 \ \frac{10- 0.2 \ 20}{ 10 \ +\ 20}

             a = 9.8 (6/30)

             a = 1.96 m / s²

a) now we can use the kinematic relations

             y = v₀ t + ½ a t²

the blocks come out of rest so their initial velocity is zero

             y = ½ a t²

             y = ½ 1.96 t²

             y = 0.98 t²

for t = 1s y = 0.98 m

       t = 2s y = 1.96 m

b) Time is a scale that is the same for the entire system, the question should be oriented to how far the big block will move.

As the curda is in tension the two blocks must move the same distance

c) the velocity of the block M

           v = vo + a t

           v = 0 + 1.96 t

for t = 1 s v = 1.96 m / s

       t = 2 s v = 3.92 m / s

d) the deceleration if the chain is cut

when removing the chain the tension becomes zero

           -fr = M a

          - μ M g = M a

          a = - μ g

          a = - 0.2 9.8

          a = -1.96 m / s²

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         v² = vo² - 2 a x

        0 = vo² - 2a x

        x = vo² / 2a

        x = 1.96² / 2 1.96

        x = 0.98 m

the time to travel this distance is

        v = vo - a t

        t = vo / a

        t = 1.96 /1.96

        t = 1 s

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