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riadik2000 [5.3K]
2 years ago
9

Determine if a sentence is an argument?​

Physics
1 answer:
Aneli [31]2 years ago
5 0

Answer:

The tone really matters and if there are any exclamation marks also.

Explanation:

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In 4 -5 sentences, summarize the science of the sport of curling and how it relates to friction
zalisa [80]
Well, a curler uses heat to calm down friction so I am not sure
5 0
3 years ago
A fly travels along the x-axis. His starting point is x = 16 m and his ending point 15x = - 25 m. His flight lasts 4.0 seconds H
gogolik [260]

Explanation:

Starting position at x  = 16m

Ending position at x  = -25m

Time of flight  = 4s

Unknown:

Distance flown  = ?

Displacement  = ?

Speed  = ?

Velocity  = ?

Solution:

To find the distance flown, we should understand that the body is moving on the x - plane;  

  So distance  = 16 + 25  = 41m

Displacement is 41m to the left or -x axis

Speed is the distance divided by the time taken;

      Speed  = \frac{distance}{time}   = \frac{41}{4}   = 10.25m/s

Velocity is 10.25m/s along -x axis

5 0
3 years ago
10. 1. Why is Newton's law of gravitation called universal law ?​
Eduardwww [97]

Newtons law of gravitation is called the universal law of gravitation because it is applicable for all masses at all distances, independent of the medium.

6 0
2 years ago
Read 2 more answers
What is the freezing point of an aqueous solution that boils at 101 degrees C? Kfp = 1.86 K/m and Kbp = 0.512 K/m. Enter your an
astra-53 [7]

Answer:

-3.63 degree Celsius

Explanation:

We are given that

Boiling point of solution=T_b=101^{\circ} C

Boiling point water=100 degree Celsius

K_f=1.86K/m

K_b=0.512 K/m

\Delta T_b=T-T_0

Where T=Boiling point of solution

T_0=Boiling point of pure solvent

\Delta T_b=101-100=1^{\circ}C

\Delta T_b=k_bm

Using the formula

1=0.512\times m

Molality,m=\frac{1}{0.512} m

\Delta T_f=k_fm

Using the formula

\Delta T_f=\frac{1}{0.512}\times 1.86

\Delta T_f=3.63 C

We know that

\Delta T_f=T_0-T_1

Where T_0 =Freezing point of solvent

T_1= Freezing point of solution

Using the formula

3.63=0-T_1

Freezing point of water=0 degree Celsius

T_1=0-3.63=-3.63 C

Hence, the freezing point of solution=-3.63 degree Celsius

7 0
3 years ago
A bag of firewood has a mass of 10.0 kilograms and a weight of
lorasvet [3.4K]
90 kilograms hope this helps
8 0
3 years ago
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