1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Elanso [62]
3 years ago
15

What are the two ways to determine the negative leg of an LED?

Physics
1 answer:
ziro4ka [17]3 years ago
6 0
There are three main ways to find which end is positive and negative on LED.  First there is occasionally on the base of the LED<span> a flat part which you would use to identify that as the negative end. Second way is to look at the length of the ends occasionally they will both be the same size, but most of the time the negative end will be shorter. And finally, LED the electrodes of the negative one is the larger of the two. </span>
You might be interested in
Choose true or false for each statement regarding a parallel plate capacitor.. The voltage of a disconnected charged capacitor i
OlgaM077 [116]

Answer:

Explanation:

The voltage of a disconnected charged capacitor increases when the plate area is decreased.

When plate area decreases , capacitance C decreases , but charge Q remains constant .

Q = C V where C is capacitance and V is voltage .

when C decreases , V increases for keeping Q constant .

So the statement is true.

The electric field is dependent on the charge density on the plates.

This statement is true .

The voltage of a connected charged capacitor remains the same when the plate area is decreased .

For a connected capacitor , V or voltage is constant which is equal to voltage of charging battery .

So the statement is true .

3 0
3 years ago
Two guitarists attempt to play the same note of wavelength 6.48 cmcm at the same time, but one of the instruments is slightly ou
k0ka [10]

The answer is λ₂ = 6.48 cm or  6.52 cm.

The out-of-tune guitar may have a wavelength between "6.48 cm" and "6.52 cm."

fb = |f2 − f1|

f₁ = 343/0.064

= 5276Hz

f₂ = 5276.9 Hz ± 17 Hz

f₂ = 5293.9 Hz or 5259.9 Hz

Now, calculating the possible wavelengths:

λ = 343/ 5259.9  or 343/ 5293.9

λ₂ = 6.48 cm or 6.52 cm

<h3>Why is beat frequency important?</h3>

When two waves with almost identical frequencies traveling in the same direction collide at a certain location, beats are produced. The opposing beneficial and harmful disruption causes the sound to alternatively be loud and weak whenever two sound waves with different frequencies reach your ear. This is referred to as beating.

The entire value of the frequency difference between the two waves is the beat frequency.

The following formula yields the beat frequency:

fb = |f2 − f1|

Learn more about beat frequency here:

brainly.com/question/14705053

#SPJ4

5 0
2 years ago
Read 2 more answers
To develop muscle tone, a woman lifts a 2.50 kg weight held in her hand. She uses her biceps muscle to flex the lower arm throug
Romashka [77]

To solve this problem we will use the concepts related to Torque as a function of the Force in proportion to the radius to which it is applied. In turn, we will use the concepts of energy expressed as Work, and which is described as the Torque's rate of change in proportion to angular displacement:

\tau = Fr

Where,

F = Force

r = Radius

Replacing we have that,

\tau = Fr

\tau = 21cm (\frac{1m}{100cm})* 550N

\tau = 11.55Nm

The moment of inertia is given by 2.5kg of the weight in hand by the distance squared to the joint of the body of 24 cm, therefore

I = 0.25Kg\cdot m^2 +(2.5kg)(0.24m)^2

I = 0.394kg\cdot m^2

Finally, angular acceleration is a result of the expression of torque by inertia, therefore

\tau = I\alpha \rightarrow \alpha = \frac{\tau}{I}

\alpha = \frac{11.55}{0.394}

\alpha = 29.3 rad/s^2

PART B)

The work done is equivalent to the torque applied by the distance traveled by 60 °° in radians (\pi / 3), therefore

W = \tau \theta

W = 11.5* \frac{\pi}{3}

W = 12.09J

4 0
3 years ago
A horizontal spring with spring constant 950 N/m is attached to a wall. An athlete presses against the free end of the spring, c
OLga [1]

Answer:

66.5N

Explanation:

F = kx

Where F = force

K = spring constant

x = compression

Given

K = 950N/m

x = 7.0cm

F = ?

First convert the compression to meters .

7.0cm = 7.0 x 0.01

= 0.07 meters

Therefore

F = 950 x 0.07

= 66.5N

4 0
3 years ago
in the design a thermos lab, you compared the temperature of your thermos with a container that you did not insulate. what was t
irina [24]
To see if the insulation would affect the temp of whatever you are measuring. <span />
4 0
3 years ago
Other questions:
  • What is the five things to do in P.E
    14·2 answers
  • A refrigerator _ objects placed inside it.
    9·2 answers
  • How much heat energy in megajoules is needed to convert 7 kilograms of ice at -9c to water at 0c
    5·2 answers
  • If a CD player uses a 12-V battery and draws 2.0 amps of current, how much power does it use?
    5·1 answer
  • An object is shot upwards, from the ground, with an initial velocity of 120
    13·1 answer
  • Which has high frequency? i never figure this out
    12·1 answer
  • In the United States, household electric power is provided at a frequency of 60 HzHz, so electromagnetic radiation at that frequ
    6·1 answer
  • Animal-vehicle collisions can happen any time of the year, but_______ is the peak season for deer- car collisions.
    7·2 answers
  • A 2.0-kg mass swings at the end of a light string (length = 3.0 m). Its speed at the
    12·1 answer
  • In part a, (a) why did you set the frequency of the square wave to 0.40 hz? (b) what would have happened if you had set the freq
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!