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Aliun [14]
3 years ago
9

Salim has 5 boxes of paint jars. Each box has the same number of paint jars. His teacher gives him 6 more paint jars. Now he has

41 paint jars. How many paint jars were in each box
Mathematics
1 answer:
olchik [2.2K]3 years ago
5 0

Answer:

7 jars per box

Step-by-step explanation:

He now has 41 jars. How many did he have before his teacher gave him 6?

Well, 41-6=35. He had 35 jars before his teacher gave him more.

It says there was an equal amount of jars in each box. There are 5 boxes. Divide the total amount of jars (35) by the amount of boxes to find out how many jars are in each box.

35 jars / 5 boxes = 7 jars / box

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Formula of trigonomtery sin cos tan
Sergeu [11.5K]
Sin = Opposite/Hypotenuse
Cos= Ajacent/Hypotenuse
Tan= Opposite/Adjacent
6 0
4 years ago
Jamison graphs the function ƒ(x) = x4 − x3 − 19x2 − x − 20 and sees two zeros: −4 and 5. Since this is a polynomial of degree 4
Art [367]

We are given polynomial function f(x)=x^4-x^3-19x^2-x-20

We are given two zeros -4 and 5.

Therefore, x=-4 and x=5 is given.

So, the two factors of the polynomial will be (x+4)(x-5).

Let us write some steps to factor the given polynomial.

Let us take above factor (x+4) first.

On factoring (x+4) we get factors

x^4-x^3-19x^2-x-20=\left(x+4\right)\left(x^3-5x^2+x-5\right)

\mathrm{:Let \ us \ factor}\:x^3-5x^2+x-5 \ now.

Grouping

=\left(x^3-5x^2\right)+\left(x-5\right)

Factoring out gcf from each group, we get

=x^2\left(x-5\right)+\left(x-5\right)

=\left(x-5\right)\left(x^2+1\right)

So, the final factored form of given polynomial will be

x^4-x^3-19x^2-x-20=\left(x+4\right)\left(x-5\right)\left(x^2+1\right)

For first to factors (x+4) and (x-5) we have given roots: -4 and 5.

Let us find the root of third factor we got.

x^2+1=0

Subtracting both sides by 1.

x^2 = - 1.

On taking square root on both sides, we get a square root(-1)

x=\sqrt{-1}=+ i and -i.

Those are imaginary solutions.

Therefore, correct option is B) No, there are two imaginary solutions.



5 0
4 years ago
Y-3=(x+2)^2<br><br> Please explain how you graph this and find the vertex and axis of symmetry
bija089 [108]
Okay so I attatched pictures of my work. I would just graph it by plugging in x-values on either side of the vertex into the equation. For example, the vertex is at (-2,3). So try plugging x=-5 and x=1 into the equation (y=a(x-h)^2 +k).
y=(x+2)^2 +3
y=((1)+2)^2 +3=(3)^2+3= 9+3= 12 
Now you can plot the vertex (-2,3), the point (1,12), and (-5,12). From there just connect the dots and you should get a graph that looks similar to the last picture I attached. Hope this all made sense sorry it was so wordy I just wasn't sure how much you knew or didn't know. So, I thought it would be better to explain it all rather than not enough. 


8 0
3 years ago
If
Allisa [31]

Answer:

t= 0

Step-by-step explanation:

Using the rules of logarithms

log x + log y = log(xy)

log_{b} 1 = 0

Given

log_{x} a + log_{x} \frac{1}{a} = t ,then

log_{x} (a × \frac{1}{a} ) = t

log_{x} 1 = t , thus

t = 0

7 0
3 years ago
Read 2 more answers
How would u find the answer idk if they would still be the same and you just have to find that one missing angle?
ivolga24 [154]
Well... with the information you are given you just have to assume they are congruent triangles. The first picture looks like a right triangle, but the angle is 100 not 90... so it wouldn't actually look like that.

So for the missing angle all you do is 180= 100+ 55 + x

x=25

Then just match up the angles with the other triangle, they would be the same. K with F, J with G, and so on
8 0
4 years ago
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