All categories

3 years ago

If the current through a resistor is cut in half, how does the power dissipated by the resistor change? (P=0VI=1^ 2 R= V^ 2 R )

Physics

1 answer:

dimaraw [331]3 years ago

8 0

Answer:

1/4

Explanation:

P = IV, and V = IR, so P = I²R.

If R is held constant, and I is cut in half, then power becomes:

P = (I/2)²R

P = 1/4 I²R

So the power reduces by a factor of 4.

You might be interested in

Is the following chemical equation balanced? MgI2 + Br2 MgBr2 + I2 yes no

Brums [2.3K]

Yes

Explanation:

This chemical equation:

$Mg I_2 + Br_2 \rightarrow Mg Br_2 + I_2$

is balanced, because the number of atoms of each element is the same on the reactant side and on the product side. In fact:

- Mg: one atom on the left, one on the right

- I: 2 atoms on the left, and 2 on the right

- Br: 2 atoms on the left, and 2 on the right

So, the reaction is balanced.

3 0

3 years ago

Read 2 more answers

A car travel adistance of 45M in 35second What is the Speed of acar Give you answer in km/hr

Vika [28.1K]

10km/hr or 80mph is the possible answer I can give

3 0

3 years ago

Describe 2 things that happen to a DC motor when physical load (like the weight) Increases

tino4ka555 [31]

Answer:

As the load increases the motor generally reduces rpm, as the happens the counter emf generated in the armature decreases, causing more current to flow to

Explanation:

6 0

3 years ago

What is the spring constant (in n/m) of a spring that stores 100 J of elastic potential energy when it is stretched 5 m?

kogti [31]

Answer:

8N/m

Explanation:

The elastic potential energy stored can be calculated using the equation:

elastic potential energy = 0.5 × spring constant × (extension)2

assuming it is not stretched beyond the limit of proportionality.

Then calculate using the values in the question:

100J = 0.5 × spring constant × 5²

200J = spring constant × 25

spring constant = 200J ÷ 25m²

spring constant = 8J/m²

spring constant = 8N/m

8 0

4 years ago

If a ball that is 10 meters above the ground is thrown horizontally at 5.51 meters per second. a. how long will it take for the

GalinKa [24]

Answer:

a. t = 1.43 s

b. d = 7.88 m

Explanation:

a. The time of flight can be found using the following equation:

$y_{f} = y_{0} + v_{0_{y}}t - \frac{1}{2}gt^{2}$

Where:

$y_{f}$ : is the final height = -10 m

$y_{0}$ : is the initial height = 0

$v_{0_{y}}$ : is the initial speed in the vertical direction = 0

g: is the acceleration due to gravity = 9.81 m/s²

By solving the above equation for "t" we have:

$t = \sqrt{\frac{2y_{f}}{g}} = \sqrt{\frac{2*10 m}{9.81 m/s^{2}}} = 1.43 s$

Hence, the ball will hit the ground in 1.43 s.

b. The distance in the horizontal direction can be found as follows:

$x_{f} = x_{0} + v_{0}t + \frac{1}{2}at^{2}$

Where:

x₀: is the initial position in the horizontal direction = 0

a: is the acceleration in the horizontal direction = 0 (it is moving at constant speed)

$x_{f} = 5.51 m/s*1.43 s = 7.88 m$

Therefore, the ball will travel 7.88 m before it hits the ground.

I hope it helps you!

4 0

3 years ago