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Reptile [31]
3 years ago
7

A car travel adistance of 45M in 35second What is the Speed of acar Give you answer in km/hr​

Physics
1 answer:
Vika [28.1K]3 years ago
3 0
10km/hr or 80mph is the possible answer I can give
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A ball is dropped from a cliff and has an acceleration of 9.8 m/s^2 how long will it take the ball to reach a speed of 24.5 m/s
Fiesta28 [93]
<span>Acceleration of ball (a) = 9.8 m/s^2 Speed (v) = 24.5 m/s Time (t) = Acceleration / Time = v / a = 24.5/9.8 = 2.5 s So it will take 2.5 seconds to reach that speed.</span>
5 0
3 years ago
check the correctness of physical equation f is equals to MV square upon R where f is the centripetal force acting on a body of
Bas_tet [7]

Answer:

We know ForceF=mass×acceleration----------(1)

And given ForceF=

r

mv

2

----------(2)

Equating 1 and 2 dimensionaly we get ,

ma=

r

mv

2

MLT

−2

=ML

2

T

−2

L

−1

MLT

−2

=MLT

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8 0
3 years ago
Una pelota se desliza hacia arriba por una pendiente se halla inicialmente a 6m de la parte más baja de dicha pendiente y tiene
jolli1 [7]

Answer:

a) vprom = - 0.6 [m/s] b) ver explicacion c) vf = 10.8 [m/s]

Explanation:

Para poder solucionar este problema debemos completar el enunciado del problema así como la pregunta, realizando una búsqueda en Internet encontramos el enunciado completo, así como la pregunta.

"Una pelota que se desliza hacia arriba por una pendiente se halla inicialmente a 6 m de la parte más baja de dicha pendiente y tiene una velocidad de 4 m/s. Cinco segundos después se encuentra a 3 m de la parte más baja. Si suponemos una aceleración constante, "

¿cual fue la velocidad media?

¿Cuál es el significado de una velocidad media negativa?

¿Cuáles son la aceleración media y la velocidad final?

Para facilitar esta solución debemos realizar un esquema del movimiento de la pelota en el plano inclinado. En la imagen adjunta se puede ver un esquema del movimiento de la pelota sobre el plano inclinado en los diferentes tiempos mencionados.

<u>¿cual fue la velocidad media?</u>

<u />

La velocidad media se debe calcular utilizando la expresión de velocidad = espacio / tiempo.

v_{prom}=x/t\\v_{prom}=(3-6)/5\\v_{prom}=-0.6 [m/s]

<u>¿Cuál es el significado de una velocidad media negativa? </u>

La velocidad media negativa significa que se dirige hacia abajo en sentido contrario

<u>¿Cuáles son la aceleración media y la velocidad final?</u>

<u />

x=v_{o}*t+0.5*a*t^{2} \\-3=(4)*(5)+0.5*a*(5)^2\\a=1.36[m/s^2]\\\\Velocity\\v_{f}=v_{o}+a*t = 4+(1.36*5)\\v_{f}=10.8[m/s]

6 0
3 years ago
Can someone pls help me with this?
alexira [117]
C because they are both going in a constant speed
6 0
3 years ago
An aircraft is at a standstill. It accelerates to 140kts in 28 seconds. The aircraft weighs 28,000 lbs. How many feet of runway
stiv31 [10]

Answer:

runway use is 3307.8 feet

Explanation:

given data

velocity = 140 kts = 140 × 0.5144 m/s = 72.016 m/s

time = 28 seconds

weight = 28000 lbs

to find out

How many feet of runway was used

solution

we will use here first equation of motion for find acceleration

v = u + at     ..............1

here v is velocity given and u is initial velocity that is 0 and a is acceleration and t is time

put here value in equation 1

72.016 = 0 + a(28)

a = 2.572 m/s²

and

now apply third equation of motion

s = ut + 0.5×a×t²    .......................2

here s is distance and u is initial speed and t is time and a is acceleration

put here all value in equation 2

s = 0 + 0.5×2.572×28²  

s = 1008.24 m = 3307.8 ft

so  runway use is 3307.8 feet

5 0
3 years ago
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