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musickatia [10]
2 years ago
9

Heating a metal from room temperature to pouring temperature in a casting operation depends on all of the following properties e

xcept which one: (a) density, (b) heat of fusion, (c) melting temperature, (d) specific heat, or (e) thermal expansion?
Physics
1 answer:
lapo4ka [179]2 years ago
7 0

Answer:

(e) thermal expansion

Explanation:

The density, the heat of fusion and the melting temperature of the metal are determining characteristics to take into account to raise the temperature of the metal from room temperature to the melting temperature. Since they will determine the following:

Density: is the relationship between the mass of a body and the volume it occupies in outer space.

Heat of fusion: The enthalpy of fusion or heat of fusion is the amount of energy needed to make a mole of an element that is at its melting point pass from the solid state to the liquid, at constant pressure.

Melting temperature is defined as the temperature at which the phase transition from the solid state to the liquid occurs at normal atmospheric pressure.

While the dilution of metals will only have an influence on the volume it will occupy but not on the heating process

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What is the energy of a photon whose frequency is 6.0 x 10^20?
omeli [17]

Answer:

3.75 MeV

Explanation:

The energy of the photon can be given in terms of frequency as:

E = h * f

Where h = Planck's constant

The frequency of the photon is 6 * 10^20 Hz.

The energy (in Joules) is:

E = 6.63 x10^(-34) * 6 * 10^(20)

E = 39.78 * 10^(-14) J = 3.978 * 10^(-13) J

We are given that:

1 eV = 1.06 * 10^(-19) Joules

This means that 1 Joule will be:

1 J = 1 / (1.06 * 10^(-19)

1 J = 9.434 * 10^(18) eV

=> 3.978 * 10^(-13) J = 3.978 * 10^(-13) * 9.434 * 10^(18) = 3.75 * 10^(6) eV

This is the same as 3.75 MeV.

The correct answer is not in the options, but the closest to it is option C.

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Sodium and phosphorus combine to form Na3P. The name of this compound is .
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Assuming that each nucleus is roughlyspherical and that its mass is roughly equal to A (in atomic mass units {\rm u}), what is t
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Answer:

ρ/ρ2 = 3 / R₀       the two densities are different

Explanation:

Density is defined as

       ρ = M / V

As the nucleus is spherical

       V = 4/3 π r³

Let's replace

      ρ = A / (4/3 π R₀³)

      ρ = ¾ A / π R₀³

b)

      ρ2 = F / area

The area of ​​a sphere is

     A = 4π R₀²

     ρ2 = F / 4π R₀²

     ρ2 = F / 4π R₀²

Atomic number is the number of protons in the nucleon in not very heavy nuclei. This number is equal to the number of neutrons, but changes in heavier nuclei, there are more neutrons than protons.

Let's look for the relationship of the two densities

     ρ/ρ2 = ¾ A / π R₀³ / (F / 4π R₀²)

     ρ /ρ2 = 3 (A / F) (1 / R₀)

In this case it does not say that the nucleon number is A (F = A), the relationship is

     ρ/ρ2 = 3 / R₀

I see that the two densities are different

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