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VikaD [51]
3 years ago
13

A puppy is running with a speed of 11.2 m/s towards it owner when it

Physics
1 answer:
Levart [38]3 years ago
8 0

Answer:

-5.6m/s²

Explanation:

Given parameters:

Initial speed  = 11.2m/s

Time of running  = 2s

Unknown:

Acceleration of the puppy  = ?

Solution:

Acceleration is the rate of change of velocity with time.

So;

   Acceleration  = \frac{Final speed  - initial speed }{time}  

final speed  = 0m/s

 Acceleration  = \frac{0 - 11.2}{2}    = -5.6m/s²

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Read 2 more answers
A 2000 kg truck traveling north at 34 km/h turns east and accelerates to 58 km/h. (a) What is the change in the truck's kinetic
barxatty [35]

Explanation:

It is given that,

Mass of the truck, m = 2000 kg

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Final velocity of the truck, v = 58 km/h = 16.11 m/s

(a) Change in truck's kinetic energy, \Delta E=\dfrac{1}{2}m(v^2-u^2)

\Delta E=\dfrac{1}{2}\times 2000\ kg\times (16.11^2-9.44^2)

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6 0
4 years ago
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