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Irina18 [472]
3 years ago
8

Is the following chemical equation balanced? MgI2 + Br2 MgBr2 + I2 yes no

Physics
2 answers:
pashok25 [27]3 years ago
5 0

Answer:

yes

Explanation:

Brums [2.3K]3 years ago
3 0

Yes

Explanation:

This chemical equation:

Mg I_2 + Br_2 \rightarrow Mg Br_2 + I_2

is balanced, because the number of atoms of each element is the same on the reactant side and on the product side. In fact:

- Mg: one atom on the left, one on the right

- I: 2 atoms on the left, and 2 on the right

- Br: 2 atoms on the left, and 2 on the right

So, the reaction is balanced.

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Radiation measured in emissions/sec is called the curie. <br> a. True<br> b. False
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At a given instant an object has an angular velocity. It also has an angular acceleration due to torques that are present. There
katen-ka-za [31]

a) Constant

b) Constant

Explanation:

a)

We can answer this question by using the equivalent of Newton's second law of motion of rotational motion, which can be written as:

\tau_{net} = I \alpha (1)

where

\tau_{net} is the net torque acting on the object in rotation

I is the moment of inertia of the object

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\alpha = \frac{\Delta \omega}{\Delta t}

where

\Delta \omega is the change in angular velocity

\Delta t is the time interval

So we can rewrite eq.(1) as

\tau_{net}=I\frac{\Delta \omega}{\Delta t}

In this problem, we are told that at a given instant, the object has an angular acceleration due to the presence of torques, so there is a non-zero change in angular velocity.

Then, additional torques are applied, so that the net torque suddenly equal to zero, so:

\tau_{net}=0

From the previous equation, this implies that

\Delta \omega =0

Which means that the angular velocity at that instant does not change anymore.

b)

In this second case instead, all the torques are suddenly removed.

This also means that the net torque becomes zero as well:

\tau_{net}=0

Therefore, this means that

\Delta \omega =0

So also in this case, there is no change in angular velocity: this means that the angular velocity of the object will remain constant.

So cases (a) and (b) are basically the same situation, as the net torque is zero in both cases, so the object acts in the same way.

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Can an argon atom undergo vibrational motion?
azamat
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