Answer:
W = Fd = KE =1/2mv²
Explanation:
not sure if that's what your looking for but i'm pretty sure this is it.
The strength of the gravitational forces between two masses depends on
-- the product of the masses,
-- the distance between their centers of mass.
The more energy orbits the radiation jumps the more energy it has. So if the frequency stays the same each time then the wavelength will get longer if there is more energy.
In this case the situation in which the radiation jumps the most energy orbits is when: the electron jumps from the fourth orbit to the first orbit. This will emit the longest wavelength
Answer:
ΔR = 9 s
Explanation:
To calculate the propagation of the uncertainty or absolute error, the variation with each parameter must be calculated and the but of the cases must be found, which is done by taking the absolute value
The given expression is R = 2A / B
the uncertainty is ΔR = |
| ΔA + |
| ΔB
we look for the derivatives
= 9 / B
= 9A (
)
we substitute
ΔR =
ΔA +
ΔB
the values are
ΔA = 2 s
ΔB = 3 s
ΔR =
2 +
3
ΔR = 1.636 + 7.14
ΔR = 8,776 s
the absolute error must be given with a significant figure
ΔR = 9 s
Answer:
The velocity is 
Explanation:
From the question we are told that
The frequency of the signal sent out is 
The frequency of the signal received is 
The speed of sound is 
Generally the frequency of the sound received is mathematically represented as
![f_r = f_s [\frac{v_s + v}{v_s - v} ]](https://tex.z-dn.net/?f=f_r%20%3D%20%20f_s%20%20%5B%5Cfrac%7Bv_s%20%20%2B%20v%7D%7Bv_s%20%20-%20v%7D%20%5D)
where v is the velocity of the object
=> ![40 *10^{3} = 38 *10^{3} * [\frac{341 + v}{341 - v} ]](https://tex.z-dn.net/?f=40%20%2A10%5E%7B3%7D%20%3D%20%2038%20%2A10%5E%7B3%7D%20%2A%20%20%20%5B%5Cfrac%7B341%20%20%2B%20v%7D%7B341%20%20-%20v%7D%20%5D)
=> 
=> 
=> 
=> 