Answer: 117.60N
Explanation:
Weight is a force. Therefore, we can use the force formula to find weight.
![Formula: W=m*g](https://tex.z-dn.net/?f=Formula%3A%20W%3Dm%2Ag)
W = weight
m = mass
g = acceleration due to gravity (
)
![W=(12kg)(9.8m/s^2)\\W=117.60N](https://tex.z-dn.net/?f=W%3D%2812kg%29%289.8m%2Fs%5E2%29%5C%5CW%3D117.60N)
I'm not sure...
I feel ya.
Answer:
a) 32.58 m/s²
b) 161.84 m/s
Explanation:
Initial velocity = u = 0
Final velocity = v = 145 m/s
Time taken = t = 4.45 s
s = Displacement of dragster = 402 m
a = Acceleration
![v=u+at\\\Rightarrow a=\frac{v-u}{t}\\\Rightarrow a=\frac{145-0}{4.45}\\\Rightarrow a=32.58\ m/s^2](https://tex.z-dn.net/?f=v%3Du%2Bat%5C%5C%5CRightarrow%20a%3D%5Cfrac%7Bv-u%7D%7Bt%7D%5C%5C%5CRightarrow%20a%3D%5Cfrac%7B145-0%7D%7B4.45%7D%5C%5C%5CRightarrow%20a%3D32.58%5C%20m%2Fs%5E2)
![v^2-u^2=2as\\\Rightarrow v=\sqrt{2as-u^2}\\\Rightarrow v=\sqrt{2\times 32.58\times 402-0^2}\\\Rightarrow v=161.84\ m/s](https://tex.z-dn.net/?f=v%5E2-u%5E2%3D2as%5C%5C%5CRightarrow%20v%3D%5Csqrt%7B2as-u%5E2%7D%5C%5C%5CRightarrow%20v%3D%5Csqrt%7B2%5Ctimes%2032.58%5Ctimes%20402-0%5E2%7D%5C%5C%5CRightarrow%20v%3D161.84%5C%20m%2Fs)
The final velocity is greater than the velocity used to find the average acceleration due to the gear changes. The first gear in a dragster has the most amount of toque which means the acceleration will be maximum. The final gears have less torque which means the acceleration is lower here. The final gears have less acceleration but can spin faster which makes the dragster able to reach higher speeds but slowly.
<span>The observation or measurement of physical properties of matter does not change its composition or its chemical nature. Other examples of physical properties include the infrared spectrum, attraction or repulsion to magnets, viscosity and opacity.</span>
Answer:
μ=0.151
Explanation:
Given that
m= 3.5 Kg
d= 0.96 m
F= 22 N
v= 1.36 m/s
Lets take coefficient of kinetic friction = μ
Friction force Fr=μ m g
Lets take acceleration of block is a m/s²
F- Fr = m a
22 - μ x 3.5 x 10 = 3.5 a ( take g =10 m/s²)
a= 6.28 - 35μ m/s²
The final speed of the block is v
v= 1.36 m/s
We know that
v²= u²+ 2 a d
u= 0 m/s given that
1.36² = 2 x a x 0.96
a= 0.963 m/s²
a= 6.28 - 35μ m/s²
6.28 - 35μ = 0.963
μ=0.151