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3 years ago

Can two people do different work, but have the same power?

2 answers:

8 0

Of course !

I lift 1 kilogram 1 meter in 1 second.
You lift 60 kilograms 2 meters in 2 minutes.

My work is 9.8 joules.
Your work is 1,176 joules.

My power is 9.8 watts.
Your power is also 9.8 watts.

Lelechka [254]3 years ago

7 0

Yes, two people can do different work and have the same power.

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which of the following describes the principle of conversation of charge? a.charge is created b. a charge can be transferred c.

victus00 [196]

B) in Physics, charge conservation is the principle that the total electric charge in an isolated system never changes. The net quantity of electrical charge, the amount of positive charge minus the amount of negative charge in the universe is always conserved.

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4 years ago

Does gravity affect your weight???

Degger [83]

Weight is a force caused by gravity. The weight of an object is the gravitational force between the object and the Earth. The more mass the object has the greater its weight will be.

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3 years ago

Read 2 more answers

If the net force acting on an object is zero, its inertia is also zero.<br> True or false

S_A_V [24]

Answer:

its false

Explanation:

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3 years ago

A 1100 kg car rounds a curve of radius 68 m banked at an angle of 16 degrees. If the car is traveling at 95 km/h, will a frictio

Mariulka [41]

Answer:

Yes. Towards the center. 8210 N.

Explanation:

Let's first investigate the free-body diagram of the car. The weight of the car has two components: x-direction: towards the center of the curve and y-direction: towards the ground. Note that the ground is not perpendicular to the surface of the Earth is inclined 16 degrees.

In order to find whether the car slides off the road, we should use Newton's Second Law in the direction of x: F = ma.

The net force is equal to $F = \frac{mv^2}{R} = \frac{1100\times (26.3)^2}{68} = 1.1\times 10^4~N$

Note that 95 km/h is equal to 26.3 m/s.

This is the centripetal force and equal to the x-component of the applied force.

$F = mg\sin(16) = 1100(9.8)\sin(16) = 2.97\times10^3$

As can be seen from above, the two forces are not equal to each other. This means that a friction force is needed towards the center of the curve.

The amount of the friction force should be $8.21\times 10^3~N$

Qualitatively, on a banked curve, a car is thrown off the road if it is moving fast. However, if the road has enough friction, then the car stays on the road and move safely. Since the car intends to slide off the road, then the static friction between the tires and the road must be towards the center in order to keep the car in the road.

5 0

4 years ago

HELP ASAP! <br>why is rolling friction much smaller than sliding friction? Also give an example.

IceJOKER [234]

Answer:

Rolling friction is much smaller than sliding friction because Rolling friction is considerably less than sliding friction as there is no work done against the body that is rolling by the force of friction. For a body to start rolling a small amount of friction is required at the point where it rests on the other surface, else it would slide instead of roll.

Rolling Friction example: Anything with weels (cars,skateboards) or a ball rooling.

Sliding Friction example: Bicycle brakes,skinning your knee walking,writing.

6 0

3 years ago