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Brrunno [24]
2 years ago
11

The maximum solubility of Ag2CO3 in 0.02M Na2CO3 is (Ksp ofAg2003 is 8 x 10-12)​

Chemistry
1 answer:
Anna007 [38]2 years ago
3 0

The maximum solubility of Ag₂CO₃ = = 1 x 10⁻⁵

<h3>Further explanation</h3>

Given

0.02 M Na₂CO₃

Ksp of  Ag₂CO₃ is 8 x 10⁻¹²

Required

The solubility of Ag₂CO₃

Solution

Ag₂CO₃ ⇒ 2Ag⁺ + CO₃²⁻

s                  2s        s

s = solubility

Ksp Ag₂CO₃ = [Ag⁺]² [CO₃²⁻]

Ksp Ag₂CO₃ = (2s)².s

Ksp Ag₂CO₃ = 4s³

In 0.02 M Na₂CO₃ ⇒ 2Na⁺ + CO₃²⁻⇒ [ CO₃²⁻]=0.02, so Ksp Ag₂CO₃ :

8 x 10⁻¹² = [2s]² [0.02]

8 x 10⁻¹² = 4s² [0.02]

4s² = 8 x 10⁻¹² / 2 × 10⁻²

4s² = 4 x 10⁻¹⁰

s² = 1 x 10⁻¹⁰

s = √1 x 10⁻¹⁰

s = 1 x 10⁻⁵

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Levart [38]

Given,  half life of a certain radioactive element = 800 years.

Amount of substance remaining at time t = 12.5%

Lets consider the initial amount of the radioactive substance  = 100%

Using the half life equation:

A = A₀(1/2)^t/t₁/₂

where A₀ is the amount of radioactive substance at time zero and A is the amount of radioactive substance at time t, and t₁/₂ is the half-life of the radioactive substance.

Plugging the given data into the half life equation we have,

12.5 = 100 . (1/2)^t/800

12.5/100 = (1/2)^t/800

0.125 = (0.5)^t/800

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3 years ago
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8 0
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What is the pH of a 0.08 M solution of Ca(OH),?
torisob [31]

Answer:

pH = 12.20

Explanation:

Ca(OH)2 is a strong base, so it dissociates completely. A 0.08 M solution of Ca(OH)2 is 0.16 M OH-, since every mole of Ca(OH)2 has 2 OH-.

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In the titration of HCl with NaOH, the equivalence point is determined
kondaur [170]

Answer:

In the titration of HCl with NaOH, the equivalence point is determined from the point where the phenolphthalein turns pink and then remains pink on swirling.

Explanation:

The equivalence point is the point at which exactly enough titrant (NaOH) has been added to react with all of the analyte (HCl). Up to the equivalence point, the solution will be acidic because excess HCl remains in the flask.

Phenolphtalein is chosen because it changes color in a pH range between 8.3 – 10. Phenolphthalein is naturally colorless but turns pink in alkaline solutions. It remains colorless throughout the range of acidic pH levels, but it begins to turn pink at a pH level of 8.3 and continues to a bright purple in stronger alkalines.

It will appear pink in basic solutions and clear in acidic solutions.

The more NaOH added, the more pink it will be. (Until pH≈ 10)

In strongly basic solutions, phenolphthalein is converted to its In(OH)3− form, and its pink color undergoes a rather slow fading reaction and becomes completely colorless above 13.0 pH

a. from the point where the pink phenolphthalein turns colorless and then remains colorless on swirling.

⇒ the more colorless it turns, the more acid the solution. (More HCl than NaOH)

b. from the point where the phenolphthalein turns pink and then remains pink on swirling.

The equivalence point is the point where phenolphtalein turns pink and remains pink ( Between ph 8.3 and 10). (

Although, when there is hydrogen ions are in excess, the solution remains colorless. This begins slowely after ph= 10 and can be noticed around ph = 12-13

c. from the point where the pink phenolphthalein first turns colorless and then the pink reappears on swirling.

Phenolphthalein is colorless in acid solutions (HCl), and will only turn pink when adding a base like NaOH

d. from the point where the colorless phenolphthalein first turns pink and then disappears on swirling

Phenolphthalein is colorless in acid or neutral solutions. Once adding NaOH, the solution will turn pink. The point where the solution turns pink, and stays pink after swirling is called the equivalence point. When the pink color disappears on swirling, it means it's close to the equivalence point but not yet.

3 0
2 years ago
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