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Brrunno [24]
3 years ago
11

The maximum solubility of Ag2CO3 in 0.02M Na2CO3 is (Ksp ofAg2003 is 8 x 10-12)​

Chemistry
1 answer:
Anna007 [38]3 years ago
3 0

The maximum solubility of Ag₂CO₃ = = 1 x 10⁻⁵

<h3>Further explanation</h3>

Given

0.02 M Na₂CO₃

Ksp of  Ag₂CO₃ is 8 x 10⁻¹²

Required

The solubility of Ag₂CO₃

Solution

Ag₂CO₃ ⇒ 2Ag⁺ + CO₃²⁻

s                  2s        s

s = solubility

Ksp Ag₂CO₃ = [Ag⁺]² [CO₃²⁻]

Ksp Ag₂CO₃ = (2s)².s

Ksp Ag₂CO₃ = 4s³

In 0.02 M Na₂CO₃ ⇒ 2Na⁺ + CO₃²⁻⇒ [ CO₃²⁻]=0.02, so Ksp Ag₂CO₃ :

8 x 10⁻¹² = [2s]² [0.02]

8 x 10⁻¹² = 4s² [0.02]

4s² = 8 x 10⁻¹² / 2 × 10⁻²

4s² = 4 x 10⁻¹⁰

s² = 1 x 10⁻¹⁰

s = √1 x 10⁻¹⁰

s = 1 x 10⁻⁵

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If the Ksp of NaCl is experimentally determined to be 53.9, then what is the concentration of Na (in M) when it begins to crysta
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For the concentration of Na in M when it begins to crystallize out of the solution is mathematically given as

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<h3>what is the concentration of Na in M when it begins to crystallize out of the solution?</h3>

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3 years ago
What is the identity of a gas that has a density of 1.4975 g/L and a volume of 8.64 L at a pressure of 2.384 atm and with a temp
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Answer: H2O (water)

Explanation:

The answer choices for this question are:

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The solution of the problem is:

1) Data:

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volume, V = 8.64 liter
pressure, p = 2.384 atm
temperature, T = 349.6 K

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3) Solution

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