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Oduvanchick [21]
3 years ago
9

Determine if p2+14p+49 is a perfect trinomial

Mathematics
1 answer:
shusha [124]3 years ago
4 0

Answer:

Step-by-step explanation:

p²  + 14p + 49 = p² + 2 * 7p + 7²

Comparing with a² + 2ab + b²,

a= p and b = 7

So 2ab = 2*p*7 = 14 p

So, p²  + 14p + 49 is a perfect trinomial

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In your pattern which shape covers more of the plane blue rhombus red trapezoid or green triangles? Explain how you know.
mixas84 [53]

Answer:

Which shapes cover more of the plane" means that we are comparing the areas covered by the different types of shapes. In these patterns, two triangles match up to one rhombus, and three triangles match up to one trapezoid.

In both Pattern A and Pattern B, the first hexagonal part is made up of 7 triangles, 4 rhombuses, and 3 trapezoids.

The first hexagonal part is repeated across the pattern, so whichever type of shape covers the most area of this first part also covers the most area in the whole pattern.

<em>hope it helps</em>

3 0
3 years ago
Please I really need it ASAP!I'll give you brainliest! please...!!!!
nignag [31]

Answer:

5x+2 = 2x+17

=> 5x-2x = 17-2

=> 3x = 15

=> x = 15/3

=> x = 5

thats my answere

brainlieat me!!!thankyou

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3 0
2 years ago
If y = -4 when x = 10, find y when x = 5
vesna_86 [32]
To find Y you must divide two by each side, making y=-2
- I hope this helps :)
3 0
3 years ago
Read 2 more answers
What’s the answers ?
Usimov [2.4K]

hope this helps! feel free to clarify if unsure

6 0
2 years ago
The magnitude and direction of two vectors are shown in the diagram. What is the magnitude of their sum? ​
VLD [36.1K]

Separate the vectors into their <em>x</em>- and <em>y</em>-components. Let <em>u</em> be the vector on the right and <em>v</em> the vector on the left, so that

<em>u</em> = 4 cos(45°) <em>x</em> + 4 sin(45°) <em>y</em>

<em>v</em> = 2 cos(135°) <em>x</em> + 2 sin(135°) <em>y</em>

where <em>x</em> and <em>y</em> denote the unit vectors in the <em>x</em> and <em>y</em> directions.

Then the sum is

<em>u</em> + <em>v</em> = (4 cos(45°) + 2 cos(135°)) <em>x</em> + (4 sin(45°) + 2 sin(135°)) <em>y</em>

and its magnitude is

||<em>u</em> + <em>v</em>|| = √((4 cos(45°) + 2 cos(135°))² + (4 sin(45°) + 2 sin(135°))²)

… = √(16 cos²(45°) + 16 cos(45°) cos(135°) + 4 cos²(135°) + 16 sin²(45°) + 16 sin(45°) sin(135°) + 4 sin²(135°))

… = √(16 (cos²(45°) + sin²(45°)) + 16 (cos(45°) cos(135°) + sin(45°) sin(135°)) + 4 (cos²(135°) + sin²(135°)))

… = √(16 + 16 cos(135° - 45°) + 4)

… = √(20 + 16 cos(90°))

… = √20 = 2√5

5 0
3 years ago
Read 2 more answers
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