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Artist 52 [7]
3 years ago
15

Solve by factoring or finding square roots x^2-6x-7=0

Mathematics
2 answers:
uysha [10]3 years ago
7 0

Answer:

<h2>x = -1 or x = 7</h2>

Step-by-step explanation:

x^2-6x-7=0\\\\x^2+x-7x-7=0\\\\x(x+1)-7(x+1)=0\\\\(x+1)(x-7)=0\iff x+1=0\ \vee\ x-7=0\\\\x+1=0\qquad\text{subtract 1 from both sides}\\\bold{x=-1}\\\\x-7=0\qquad\text{add 7 to both sides}\\\bold{x=7}

Nata [24]3 years ago
7 0

Answer:

x = - 1, x = 7

Step-by-step explanation:

Given

x² - 6x - 7 = 0

Consider the factors of the constant term (- 7 ) which sum to give the coefficient of the x- term

The factors are - 7 and + 1, since

- 7 × 1 = - 7 and - 7 + 1 = - 6, hence

(x - 7)(x + 1) = 0

Equate each factor to zero and solve for x

x - 7 = 0 ⇒ x = 7

x + 1 = 0 ⇒ x = - 1

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If u(x) = x5 – x4 + x2 and v(x) = –x2, which expression is equivalent to (u/v)(x)
choli [55]

Answer:

c) -x^3 + x^2 - 1

Step-by-step explanation:

Given: u (x) = x^5 - x^4 +x^2 and v(x) = -x^2

(u/v)(x) = u(x)/v(x)

Now plug in the given functions in the above formula, we get

= (x^5 - x^4 + x^2) / -x^2

We can factorize the numerator.

In x^5 - x^4 + x^2. the common factor is x^2, so we can take it out and write the remaining terms in the parenthesis.

= x^2 (x^3 - x^2 + 1) / - x^2

Now we gave x^2 both in the numerator and in the denominator, we can cancel it out.

(u/v)(x) = (x^3 - x^2 + 1) / -1

When we dividing the numerator by -1, we get

(u/v)(x) = -x^3 + x^2 - 1

Answer: c) -x^3 + x^2 - 1

Hope you will understand the concept.

Thank you.

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3 years ago
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andrew11 [14]

Answer:

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Step-by-step explanation:

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zysi [14]
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The <u><em>correct answer</em></u> is:

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Explanation:

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<em>Greetings from Brasil...</em>

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